6-(2+4)
6-6
=0 Formal charge of O atoms a and b is 0
6-(1+6)
6-7
= -1 Formal charge for O atoms c is -1
Answer 0,0,-1
Answer:
So you need to look for the average speed of each car, which would allow you to then enter the numbers.
Explanation:
Hope this helps! Have a great say! :)
Acid + base = water + salt
KOH + HCl = H₂<span>O + KCl
hope this helps!
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Answer:
D. Ionic bond
Explanation:
First some definitions: ionic bonds always have metals that transfer electrons. Covalent bonds are between nonmetals that share electrons. (Sharing is caring!)
Li is a metal, so right off the bat we know this is not a covalent bond. However, it's not a metal, so we can cross off C as well. The phrase "paired bond" isn't common, so we know the answer must be D. ionic bond.
And in this bond, Li's electrons will transfer to O to make both have a full valence shell. (As opposed to covalent bonds, which share electrons, not transfer completely.)
Answer:
11.3 g/cm³
Explanation:
Data Given:
Diameter of lead ball = 10.0 mm
Convert mm to cubic centimeter (cm³)
1 mm = 0.1 cm
So,
10.0 mm = 10.0 x 0.1 = 1 cm
mass of lead ball = 5.910 g
density of of lead ball =?
Solution:
To find density formula will be used
d = m/V ...........(1)
where
d = density
m = mass
V = volume
So,
To find the density of the lead ball (sphere), first we have to find volume of the ball.
To find volume of the ball following formula will be used
V = 4 . π . r³/ 3 ..............(2)
where
π = 3.14
r = radius
So,
as
So, radius will be
r = 1 cm / 2
r = 0.5 cm
Now put values in formula 2
V = (4)(3.14)(0.5cm)³/ 3
V = (12.56)(0.125 cm³) /3
V = 1.57 cm³/3
V = 0.523 cm³
So, the volume of the lead ball is 0.523 cm³
Now put values in equation 1
d = m/V
d = 5.910 g / 0.523 cm³
d = 11.3 g/cm³
Density of the lead ball = 11.3 g/cm³
