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2 years ago

Help please!! I need to turn this in by midnight! EST

Chemistry

1 answer:

nignag [31]2 years ago

8 0

Answer:

FIREWORKS : WHEN FIREWORKS EXPLODE THEY EXPEL SMOKE WHICH IS A FORM OF GAS AND THEY LIGHT UP WHICH IS ANOTHER CHEMICAL REACTION AND OF COURSE THE WHOLE FIREWORK GETS HOT ( Temperature rises )

Explanation:

you could see your reaction happens when original substance changes in color temperature formation produces light or gas in many other things

( besides it's original form! )

answer what changed from it's original form!

ex: baking a cake:

the cake change form ( rising ) due to heat ( rising temperature )

REACTION WAS:

- formation of precipitate ( solid to settle out of a solution )

- change I'm temperature to bake the cake

Extra:

you got this!

I hope I helped even just a little!

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3 years ago

What does the peak of a probability curve for an electron in an atom indicate?

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3 years ago

Read 2 more answers

0.53g of acetanilide was subjected to kjeldahl determination and the ammonia produced was collected in 50cm3 of 0.50M of h2so4.o

Lady bird [3.3K]

Answer:

10.57% of N in acetanilide

Explanation:

All nitrogen in the sample is converted in NH₃ in the Kjeldahl determination. The NH₃ reacts with H₂SO₄ as follows:

2NH₃ + H₂SO₄ → 2NH₄⁺ + SO₄²⁻

The acid in excess in titrated with Na₂CO₃ as follows:

Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂

To solve this question we must find the moles of sodium carbonate = Moles of H₂SO₄ in excess. The added moles - Moles in excess = Moles of sulfuric acid that reacts:

Moles Na₂CO₃ anf Moles H₂SO₄ in excess:

0.025L * (0.05mol / L) = 1.25x10⁻³ moles Na₂CO₃ / 0.01360L =

0.09191M * 0.250L = 0.0230 moles H₂SO₄ in excess.

Moles H₂SO₄ added:

0.050L * (0.50mol / L) = 0.0250 moles H₂SO₄ added

Moles that react:

0.0250 moles - 0.0230 moles = 0.0020 moles H₂SO₄

Moles of NH₃ = Moles N:

0.0020 moles H₂SO₄ * (2mol NH₃ / 1mol H₂SO₄) = 0.0040 moles NH₃ = Moles N

mass N and mass percent:

0.0040 moles N * (14g / mol) = 0.056gN / 0.53g * 100 =

<h3>10.57% of N in acetanilide</h3>

7 0

2 years ago

\The specific heat of aluminum is 0.21 cal g°C . How much heat is released when a 10 gram piece of aluminum foil is taken out of

atroni [7]

Answer: The amount of heat released is 84 calories.

Explanation:

The equation used to calculate the amount of heat released or absorbed, we use the equation:

$Q= m\times c\times \Delta T$

where,

Q = heat gained or released = ? Cal

m = mass of the substance = 10g

c = specific heat of aluminium = 0.21 Cal/g ° C

Putting values in above equation, we get:

$\Delta T={\text{Change in temperature}}=(10-50)^oC=-40^oC$

$Q=10g\times 0.21Cal/g^oC\times-40^oC$

Q = -84 Calories

Hence, the amount of heat released is 84 calories.

8 0

4 years ago