divide the space between one and zero into five and put it on the section closest to one but not on it
Answer:
my answer is A. you only need substitute n from 1 to 4
Answer: option B is correct.
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
The line passes through (- 5, - 2) and (3, - 1),
y2 = - 1
y1 = - 2
x2 = 3
x1 = - 5
Slope,m = (- 1 - - 2)/(3 - - 5) = 1/8
To determine the intercept, we would substitute x = 3, y = - 1 and
m = 1/8 into y = mx + c. It becomes
- 1 = 1/8 × 3 + c
- 1 = 3/8 + c
c = - 1 - 3/8 = - 11/8
The equation becomes
y = x/8 - 11/8
the number is - 1
let the number be n then 6 times the number is 6n and added to -4 is
- 4 + 6n = 10n ( equal to 10 times the number )
subtract 6n from both sides
- 4 = 4n ( divide both sides by 4 )
= n , hence n = - 1