All categories

3 years ago

Match the independent variable, dependent variable and constant for the following statement.

Mathematics

1 answer:

den301095 [7]3 years ago

5 0

Independent: cell phone plan
dependent: monthly cost
constant: per month/per minute (money)

You might be interested in

I’ll give the Brainliest to who answers this question with a reasonable explanation.

SSSSS [86.1K]

Answer:

31136

Step-by-step explanation:

To find the how much an number increased by a percent. Divide the percent by 100. 23/100=0.23.

Then multiply 0.23 by the original number which is 25,314. Which gives us about 5822.

Then since it INCREASED, we are going to add that number it increased to the original. 25314+5822= 31136.

4 0

2 years ago

Read 2 more answers

A submarine dives at an angle of 13 degrees to the surface of the water. The submarine travels at a speed of 760 feet per minute

Bad White [126]

5 54r 4e2dwdfftye45dsww32444444re

3 0

3 years ago

Write 16^8 as a power with a base of 4

ruslelena [56]

(4^2)^8 would be the answer 4^2=16 and 16^8 is the same thing

4 0

3 years ago

Read 2 more answers

The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me

zimovet [89]

Answer:

Option D) $275

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $235

Standard Deviation, σ = $20

We are given that the distribution of amount of money spent by students is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.975

$P( X < x) = P( z < \displaystyle\frac{x - 235}{20})=0.975$

Calculation the value from standard normal z table, we have,

$P( z < 1.960) = 0.975$

$\displaystyle\frac{x - 235}{20} = 1.960\\x =274.2 \approx 275$

Approximately 97.5% of the students spent below $275 on textbook.

7 0

3 years ago

On a certain exam, Tony corrected 20 papers and found the mean for his group to be 70. Alice corrected the remaining 10 papers

son4ous [18]

Answer:

The mean of the combined group is 76.67 ≈ 77

Step-by-step explanation:

The sum of the grades in Tom's group is 20×70 = 1400
The sum of grades in Alice's group is 10×90=900
The sum of gradees in the combined group is =1400+900=2300
Then the mean grade of the combined group is $\frac{2300}{30}=76.67$

where

2300 is the sum of the all grades in the combined group
30 is the total number of people in the group

4 0

3 years ago