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Liono4ka [1.6K]
3 years ago
9

Solve using elimination. 2x – 3y = -7 -8x + 3y = 19

Mathematics
1 answer:
Brums [2.3K]3 years ago
5 0

Answer:

-2,1

Step-by-step explanation:

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Answer:

Step-by-step explanation: with what?

7 0
3 years ago
At a pumpkin patch, if Armando guesses the weight of his pumpkin within 0.3 pounds, he gets to take the pumpkin home for free. I
Reil [10]

Answer: last option

Step-by-step explanation:

You know that the weight of his pumpkin 4.9 pounds and that, if he guesses its weight within 0.3 pounds, he will get the pumpkin for free.

Then, to find the minimum weight he can guess  in order to get his pumpkin for free, it's necessary to write the expression:

x-0.3=4.9

Rewriting it:

x-4.9=0.3

To find the maximum weight he can guess  in order to get his pumpkin for free, it's necessary to write the expression:

x+0.3=4.9

Rewriting it:

x-4.9=-0.3

7 0
3 years ago
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How many solutions does the equation −2a + 2a + 7 = 8 have? One Two None Infinitely many.
jonny [76]
The answer is none. Since you have to add your a's first, your left with 0 meaning that there is no more a's meaning that you have no solution. Hope this helps!
7 0
3 years ago
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Go step by step to reduce the radical.<br> V216
oksano4ka [1.4K]

Answer:

6\sqrt{6}

Step-by-step explanation:

\sqrt{216}

factorise 216

\sqrt{2*2*2*3*3*3}

since it is square root (meaning it has index to) pair up the number

2*3\sqrt{2*3

6\sqrt{6}

6 0
3 years ago
A park is rectangular with a length of ⅔ miles. If the area of the park is 3/9 square miles, what is the width?
Zielflug [23.3K]

Answer:

Area of the rectangular park = 2/3 square mile

Let us assume the width of the rectangular park = x

Then

The length of the rectangular park = 2 2/3 * x mile

                                                      = 8x/3 mile

Then

Area of the rectangular park = Length * Width

2/3 = (8x/3) * x

2/3 = 8x^2/3

(2 * 3)/3 = 8x^2

2 = 8x^2

x^2 = 2/8

x^2 = 1/4

x^2 = (1/2)^2

x = 1/2

So the width of the park is 1/2 feet.

Step-by-step explanation:

Brainliest would be nice

4 0
3 years ago
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