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3 years ago

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Mora ate 8.5 Containers of Yogurt one week. Each Container Held 5.4 Ounces Of Yogurt . HOW Many Ounces Of Yogurt Did she eat in

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1 answer:

kvasek [131]3 years ago

6 0

45.9 ounces. 8.5 x 5.4 = 45.9 ounces of yogurt

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Right isosceles triangles are constructed on the sides of a 3−4−5 right triangle, as shown. A capital letter represents the area

Ivenika [448]

Answer:

1

Step-by-step explanation:

because the triangles are isosceles, that means that the area of Z is 5x5x1/2, which equals 12.5

the area of X is 4.5

the area of y is 8

(8+4.5)/(12.5) = 1

5 0

3 years ago

5. Write an equation for the linear<br> relationship shown below.

Neporo4naja [7]

Answer:

y=3×-11

Step-by-step explanation:

y=m+c

m=7-1÷6-4

m=6÷2

m=3

y=3+c

7=3(6)+c

7-18=c

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2 years ago

Latrell and his cousin, Tisha, met at a state park to go for an all-day hike. Latrell drove 122 miles to get to the park, and it

Naddika [18.5K]

Answer:

3 miles

Step-by-step explanation:

122/2 is 61

64 plus 32 is 96. 96/1.5 is 64 meaning that she goes 64 miles an hour.

so she goes 3 miles faster on average than latrell, with latrell going 61 an hour average and her going 64 an hour average

5 0

2 years ago

Read 2 more answers

Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.

bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

3 0

3 years ago

What is the solution of the equation when solved using the quadratic formula?<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B

Artemon [7]

Answer:

$x=\pm2i\sqrt{5}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

<u>Algebra II</u>

Imaginary Numbers: √-1 = i

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x² + 20 = 0

<u>Step 2: Identify Variables</u>

a = 1

b = 0

c = 20

<u>Step 3: Find roots </u><em><u>x</u></em>

Substitute: $x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}$
Exponents: $x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}$
Multiply: $x=\frac{-0\pm\sqrt{0-80} }{2}$
Subtract: $x=\frac{\pm\sqrt{-80} }{2}$
Factor: $x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}$
Simplify: $x=\frac{\pm4i\sqrt{5} }{2}$
Divide: $x=\pm2i\sqrt{5}$

6 0

2 years ago