Answer:
A) Age!! Its because even if the object was 1 year old or 100 years old, nothing about the impact would change. However, those other categories depict features that would definitely make an impact. For example as object that is big, fast, and hits at an angle perpendicular to whatever it is moving towards, the impact will be very lage. But if its the opposite and it was small and slow, then the impact crater would not be as large. Good luck on your quiz!!
<span>Carbon dioxide is one of the important factor in photosynthesis. It helps photosynthesis to take place and it will increase its rate provided the Oxygen supply level at night remains constant.It would probably keep increasing up to 100 percent assuming the light was on. The plant probably needs O2 at night. They generally don't make greenhouses more than about 1000 ppm because the improvement isn't worth the cost of pumping in all that extra CO2. The amount of light that the plant absorbs limits the benefit so it won't increase in proportion to the amount of CO2 past a certain point. It wouldn't be much improvement past about 5000 ppm from what I have heard before.</span>
<u>Answer:</u> The amount of heat released for 5.25 moles of hydrogen peroxide decomposed is 1032.15 kJ
<u>Explanation:</u>
We are given:
Heat released in the reaction = 196.6 kJ per mole of hydrogen peroxide
Heat released for 2 moles of hydrogen peroxide decomposed =
<u>Sign convention of heat:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
The chemical equation for the decomposition of hydrogen peroxide follows:
We are given:
Moles of hydrogen peroxide decomposed = 5.25 moles
By Stoichiometry of the reaction:
2 moles of hydrogen peroxide decomposed, the amount of heat released is 393.2 kJ
So, when 5.25 moles of hydrogen peroxide decomposed, the amount of heat released will be =
Hence, the amount of heat released for 5.25 moles of hydrogen peroxide decomposed is 1032.15 kJ