Molar mass
Ca₃(PO₄)₂ = 310 g/mol
1 mole -------------------> 310 g
2.3x10⁻⁴ mole ---------> ?
m = 2.3x10⁻⁴ * 310 / 1
m = 0.0713 g
hope this helps!
First, we need to find the atomic mass of
.
According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16
As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The
molar mass of
= 6 * 12.01 + 12 * 1.008 + 6 * 16
The
molar mass of
= 180.156
grams/moleNow that we have the molar mass of
, we can find the grams of glucose by using:
mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)
Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams
Ans: Mass of glucose in grams in 2.47 moles =
444.99 grams
-i
Answer:
c2h4o2
Explanation:
I am using my cell. This could take a bit
The Empical formula has a mass of
C 12
2H 2
O 16
total = 30
The molecular mass is given as 60 which is 2 times the empirical mass. Therefore multiply each element by 2 in the empirical formula.
You get C2H4O2
I think the answer is tenfold
hope this helps :)