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3 years ago

If 0.35 moles of kcl was dissolved in enough water to make 0.2 L of solution, what is molarity?

Chemistry

1 answer:

Mars2501 [29]3 years ago

8 0

Answer:

1.75M

Explanation:

molarity = number of moles of solute/ number of L of solution =

=0.35 mol/0.2L = 1.75 mol/L = 1.75 M

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2 years ago

Fred mixes a solution using two types of solutions: 0.60 liters containing 10% alcohol and 0.40 liters containing 35% alcohol. W

insens350 [35]

The alcohol concentration of the mixed solution is 20%

Simplification :

Based on the given condition, formulate :

35% ×0.40 + 0.6 ×10% ÷{ 0.4+0.6}

Calculate the product : $\frac{0.14+0.06}{0.4 + 0.6}$

Calculate the sum or difference : $\frac{0.2}{1}$

Any fraction with denominator 1 is equal to numerator : 0.2

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Calculate the product or quotient : $\frac{20}{100}$

A fraction with denominator equals to 100 to a percentage 20%.

How do you find the concentration of a mixed solution?

In general when your are mixing two different concentrations together first calculate number of moles for each solution (n=CV ,V-in liter) then add them together it will be total moles,then concentration of mixture will be = total moles / total volume(liter).

Learn more about concentration of alcohol :

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5 0

2 years ago

Ca+Cl2-->CaCl2 Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

kompoz [17]

Answer:

Oxidation half

Ca -----> Ca2+ +2elecyrons

Reduction half

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Explanation:

8 0

3 years ago

Which of the following sets contains a substance that could not be used as an acid base indicator?

vovangra [49]

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5 0

3 years ago

Nitric acid and nitrogen monoxide react to form nitrogen dioxide and water, like this: At a certain temperature, a chemist finds

poizon [28]

Answer:

K = 3.3

Explanation:

Nitric acid, HNO3, reacts with nitrogen monoxide, NO, to produce nitrogen dioxide, NO2 and water H2O as follows:

2HNO3(g) + NO(g) → 3NO2(g) + H2O(g)

Where equilibrium constant, K, is:

K = [NO2]³[H2O] / [HNO3]²[NO]

[] is the molar concentration of each species at equilibrium.

To solve this question we need to find molarity of each gas and replace these in the equation as follows:

[NO2] -Molar mass NO2-46.0g/mol-

18.6g * (1mol/46.0g) = 0.404mol / 7.7L = 0.0525M

[H2O] -Molar mass:18.01g/mol-

236.7g * (1mol/18.01g) = 13.14 moles / 7.7L = 1.707M

[HNO3] -Molar mass:53.01g/mol-

16.2g * (1mol/53.01g) = 0.3056 moles / 7.7L = 0.0397M

[NO] -Molar mass: 30.0g/mol-

11.0g * (1mol/30.0g) = 0.367 moles / 7.7L = 0.0476M

Replacing:

K = [NO2]³[H2O] / [HNO3]²[NO]

K = [0.0525M]³[1.707M] / [0.0397M]²[0.0476M]

4 0

3 years ago