Answer: 1.46moles
Explanation:
Applying PV= nRT
P= 1atm, V= 32.6L, R= 0.082, T = 273K
Substitute and simplify
1×32.6/(0.082×273)=n
n= 1.46moles
Answer: Gases are complicated. They're full of billions and billions of energetic gas molecules that can collide and possibly interact with each other. Since it's hard to exactly describe a real gas, people created the concept of an Ideal gas as an approximation that helps us model and predict the behavior of real gases. The term ideal gas refers to a hypothetical gas composed of molecules which follow a few rules:
Ideal gas molecules do not attract or repel each other. The only interaction between ideal gas molecules would be an elastic collision upon impact with each other or an elastic collision with the walls of the container. [What is an elastic collision?]
Ideal gas molecules themselves take up no volume. The gas takes up volume since the molecules expand into a large region of space, but the Ideal gas molecules are approximated as point particles that have no volume in and of themselves.
If this sounds too ideal to be true, you're right. There are no gases that are exactly ideal, but there are plenty of gases that are close enough that the concept of an ideal gas is an extremely useful approximation for many situations. In fact, for temperatures near room temperature and pressures near atmospheric pressure, many of the gases we care about are very nearly ideal.
If the pressure of the gas is too large (e.g. hundreds of times larger than atmospheric pressure), or the temperature is too low (e.g.
−
200
C
−200 Cminus, 200, start text, space, C, end text) there can be significant deviations from the ideal gas law.
Explanation:
Answer:
The oxidizing agent is the MnO₄⁻
Explanation:
This is the redox reaction:
10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)
Let's determine the oxidation and the reduction.
I⁻ acts with -1 in oxidation state and changes to 0, at I₂.
All elements in ground state has 0 as oxidation state.
As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.
In the permanganate (MnO₄⁻), Mn acts with +7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine
Answer:
663 g
Explanation:
Step 1: Write the balanced equation
2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃
Step 2: Calculate the moles corresponding to 825 L of CO₂
At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.
825 L × 1 mol/22.4 L = 36.8 mol
Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂
The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.
Step 4: Calculate the mass corresponding to 36.8 moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
36.8 mol × 18.02 g/mol = 663 g