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Sedaia [141]
3 years ago
10

The slope of a line is -1/5, and the y-intercept is 5. What is the equation of the line written in general form?

Mathematics
2 answers:
serg [7]3 years ago
6 0

The slope of a line is -1/5, and the y-intercept is 5. What is the equation of the line written in general form?

Answer:

x + 5y - 25 = 0

Sholpan [36]3 years ago
4 0
The general form is ax+by=c, let's first what we have to create the line in point-slope form, which is:

y-y1=m(x-x1), m=slope and (x1,y1) is any point on the line.

We are given m=-1/5 and (xy)=(0,5) so

y-5=(-1/5)(x-0)

y-5=-x/5  mutiply both sides by 5

5y-25=-x  add x to both sides

x+5y-25=0  add 25 to both sides

x+5y=25
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AfilCa [17]
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I just did trial and error. I started with 20 quarters and made changes until it worked.

4 0
3 years ago
I need help..............
vovangra [49]

Answer:

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Step-by-step explanation:

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Putting these values into the formula for the explicit rule gives ...

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4 years ago
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Svetradugi [14.3K]
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What is an equation of the line that passes through the points (6, 0) and (-1, -7)?
Orlov [11]

Answer:

y = x - 6

Step-by-step explanation:

We want to write a line in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

First, we need to find the slope, which is just the change in the y-coordinates divided by the change in the x-coordinates:

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Our equation now looks like this: y = x + b

Now, to find the y-intercept, let's use one of the points provided and plug those values of x and y into the incomplete equation we have to solve for b:

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So, the equation is: y = x - 6.

Hope this helps!

6 0
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