the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Red ! Add the corresponding x coordinates and then divide by 2. Repeat for the y values
Answer is C qwertyuiopoiuytrewertyuioiuytrewerty
Answer:
$490
Step-by-step explanation:
Shauna spent $175 on a pair of shoes.
She spent 1/9 of the remaining money on a shirt.
If he still had 4/7 of his money left,how much did he have at first ?
Solution:
Let at first, Shauna have = 
Money spent on a pair of shoes = $175
Remaining money = 
<u>As she spent 1/9 of the remaining money on a shirt.</u>
Money spent on shirt = 
As he still had 
of his money left:-
Money left = 
Money left with Shauna = Total money, she had at first -(Money spent on a pair of shoes + Money spent on shirt )
Subtracting both sides by and adding both sides by 
Taking LCM of 7 and 9, we get 63
Adding both side by -
By cross multiplication:
Dividing both sides by 180
Therefore, total $490, she had at first.
Answer:1
Step-by-step explanation: 1/2 + 1/2 is 1
