Answer:
E
Step-by-step explanation:
The problem says that triangle BDC lies in the plane k, which means that whatever angle is formed by another point beyond this plane with any of the three segments that form BDC (BD, DC, and BC) is the same as the angle formed by the line connecting the point and the plane.
Here, we're given that AD⊥DC, which means AD forms a 90° angle with DC. Then, since DC is already on the plane, we already know for sure that AD is definitely perpendicular to plane k.
Thus, the answer is E (none of these).
Answer:
u=30
x=150
z=150
y=30
Step-by-step explanation:
u=y [ being vertically opposite angle]
x+u=180[ being linear pair]
x+30=180
x=180-30
x=150
z=x[being vertically opposite angle]
z=150
y=u[ being voa]
In highest poer of placholder is 1 then it is linear
1/3x^1-2y^1=7
it is linear
yes it is
Answer:
Y = 4/3x + 0
Step-by-step explanation:
(-3,-4) and (3,4) can be plugged in to rise over run.
y 4 -(-4) = 8
x 3 - (-3) = 6
8/6 = 4/3
Plug into slope intercept form
4 = 4/3(3) + b
4 = 12/3 +b
4 = 4 +b
Subtract from both sides
0 = b
Y = 4/3x + 0
The answer would be A. -18x^7
hope this helps:)
