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mart [117]
3 years ago
8

Write an equation to solve the following. Show all your work, including the steps for solving the equation and checking your ans

wer. Clearly state your answer.
The perimeter of a rectangular photo is 72 cm. The length is twice the width.
What are the length and width of the photo?
(Hint: The formula for perimeter is 2w + 2l = P where w is the width, l is the length, and P is the perimeter.)
Answer:
Mathematics
1 answer:
vlada-n [284]3 years ago
3 0
The perimeter is 72 and P=2(L+W), furthermore, L=2W so altogether...

2(L+W)=72  and using L=2W in this we have:

2(2W+W)=72

3W=36

W=12 and since L=2W

L=24

So the length is 24cm and the width is 12cm.
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28 + 56t + 28w equivalent expressions
irina [24]

Answer:

28(1+2t+w)

Step-by-step explanation:

8 0
3 years ago
I need help someone please
IgorLugansk [536]

Answer: The answers are in the steps.

Step-by-step explanation:

A) 4 \frac{1}{2} =  9/2 * 13 =  117/2

B ) 13 ( 58  + 1/2)  

= 754  + 6.5

= 760.5

7 0
3 years ago
A bicycle store costs ​$2250 per month to operate. The store pays an average of ​$40 per bike. The average selling price of each
lesantik [10]

Answer:

75

Step-by-step explanation:

Given That :

Operation cost = $2250 per month

Purchase price per bike = $40

Average selling price per bike = $70

How many bicycles must the store sell each month to break even ;

Break even point = point at which there is net profit / loss = 0

Let number of bicycles store must sell = x

Operation cost + (purchase price * Number of bicycles) = selling price * Number of bicycles

2250 + 40x = 70x

2250 = 70x - 40x

2250 = 30x

x = 2250 / 30

x = 75

To break even 75 bicycles must be sold

5 0
3 years ago
If sinA =3/5 and A+B =90 find cosB
-Dominant- [34]

A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}

Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1

Other method:

Look at the picture.

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5

\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}

8 0
3 years ago
What times what equals 50
klasskru [66]
Twenty-five times two = fifty
8 0
3 years ago
Read 2 more answers
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