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4 years ago

8

Any force that causes an object to move in a circle is called a(n) a balanced force. b unbalanced force. c gravitational force.

d centripetal force.

2 answers:

zavuch27 [327]4 years ago

8 0

Answer- D. centripetal force

lorasvet [3.4K]4 years ago

4 0

Answer:

d

Explanation:

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Help me make a hypothesis out of this question for my project.

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Animals are able to see much more clearly in the dark than humans can.

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Humans are able to see much more clearly in the dark than animals can.

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4 years ago

What is the pressure of 5.0 mol nitrogen gas in a 2.0 L container at 286 K

g100num [7]

The "Ideal Gas Law Equations" is
$PV=nRT$
P= Pressure (in Pascals)
V=Volume (in Liters)
n=amount, or <u>n</u>umber (in moles)
R= 8.3145 $\frac{Pascals*Liters}{Moles*Kelvin}$ or $\frac{PaL}{molK}$
T= Temperature (In Kelvin)

$P= \frac{nRT}{V}$

Plug into the equation and you're good!
$P=\frac{nRT}{V}$
$P =\frac{(5mol)(8.3145)(286K)}{2L}$
$P=5944.8675Pa$

If your teacher cares about sig figs,
2 sig figs (significant figures)
$P=5900Pa$

For other units of pressure,
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4 years ago

A 25 mL sample of 0.100 M HNO3 completely reacts with NaOH according to this equation:

ASHA 777 [7]

To solve this equation you can use a basic molarity formula and substitute the correct values.

The formula for molarity is M = mol/L.

Start by changing your mL to L. To do this, divide 25 by 1000.
This results in:
.025 L

You can now rearrange your molarity formula to isolate what you are solving for, which is moles.
This leaves your formula as:
ML = mol

Now, plug in your converted volume and given molarity into the formula.
This leaves you with:
(0.100)(0.025) = mol

Multiply to find your final value for moles.
This results in:
0.0025 mol of HNO3

I hope this is what you’re looking for! :)

3 0

3 years ago

Read 2 more answers

Determine the freezing point of a 0.765 m solution of nitrobenzene in naphthalene. (given: naphthalene Kf = 7.45o C Kg/ mole and

amid [387]

Answer: The freezing point of a 0.765 m solution of nitrobenzene in naphthalene is $74.6^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(80.3-T_f)^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte such as nitrobenzene)

$K_f$ = freezing point constant = $7.45^0C/m$

m= molality = 0.765

$(80.3-T_f)^0C=1\times 7.45\times 0.765$

$T_f=74.6^0C$

Thus the freezing point of a 0.765 m solution of nitrobenzene in naphthalene is $74.6^0C$

7 0

3 years ago