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Natali [406]
3 years ago
11

Which of the following elements most readily accepts electrons? A. silicon B. chlorine C. sulfur D. phosphorus

Chemistry
1 answer:
saul85 [17]3 years ago
6 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Chemical reactivity is defined as the tendency of an element to loose of gain electrons.

Non-metals are the elements which gains electrons and hence, their chemical reactivity will be the tendency to loose electrons.

Their chemical reactivity increases as we move from left to right in a period because the valence shell come closer to nucleus as we move from left to right. So, addition of new electron in the valence shell becomes easier due to greater attraction between nucleus and valence electron.

For the given options:

<u>Option A:</u> Silicon

This element lies in Group 14 and Period 3.

<u>Option B:</u> Chlorine

This element lies in Group 17 and Period 3.

<u>Option C:</u> Sulfur

This element lies in Group 16 and Period 3.

<u>Option D:</u> Phosphorus

This element lies in Group 15 and Period 3.

Hence, chlorine will readily accept electrons due to its position in the periodic table.

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Tin is an element called Stannum and has the symbol Sn. Molar mass is the mass of 1 mol of a compound, 1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up an element or molecules making up a compound. 
While the number of atoms making up 1 mol is the same for any element, the weight of 1 mol of substance varies from one another.
In tin(Sn) molar mass - 118.71 g/mol
In 118.71 g - there's 1 mol of tin
therefore in 37.6 g of tin - 1 x 37.6 / 118.71 = 0.31 mol 
In 37.6 g of tin, there's 0.31 mol 
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The area surrounding the nucleus is called: protons electrons neutrons electron cloud
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Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500=193000C is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

14\times 1000g=14000g of copper is deposited by =\frac{193000}{63.5}\times 14000=42551181 C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

40.0=\frac{42551181 C}{t}\\\\t=1063779sec

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 1063779s\times \frac{1hr}{3600s}=295hr

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0
4 years ago
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