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IRINA_888 [86]
3 years ago
7

Given the equation a = 2(b + 6) - 10, find the value of b when a = -18.

Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Answer:

-10=b

Step-by-step explanation:

-18=2(b+6)-10

-18=2b+2

-20=2b

-10=b

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Eggs were $2.05 per dozen on January 1st and $2.00 per dozen February 1st what percent did the price decrease during January?
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This is a 2.5% decrease in price.
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The owner of a music store received a shipment of 1,532 CDs. The CDS came in 37 boxes. The same number of CDS were in 36 of the
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1532 ÷ 36 = 42 and remain 20.
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Overview
Alisiya [41]

Answer:

125.4

Step-by-step explanation:

Given

Number = 125.3546

Required

Round to 1 decimal place

Up till the first decimal place, the number is:

Number = 125.3

The digit after .3 is 5

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  • Else: approximate to 0

In this case: 5 > 4, so we approximate to 1

Add this "1" to the last digit of 125.3. This becomes 125.4

<em>Hence: when the number is approximated to 1 decimal place, the digit is 125.4</em>

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Which ratio is greater than StartFraction 5 Over 8 EndFraction? StartFraction 12 Over 24 EndFraction Three-fourths StartFraction
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Step-by-step explanation:

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Ancient paintings were found on cave walls in South America. The Carbon-14 in the paintings was measured and was found to be 19%
balu736 [363]

Answer: C. 13,839 (the answer is not among the given options, however the result is near this value)

Step-by-step explanation:

The exponential decay model for Carbon- 14 is given by the followig formula:

A=A_{o}e^{-0.0001211.t}  (1)

Where:

A is the final amount of Carbon- 14  

A_{o}= is the initial amount of Carbon- 14

t is the time elapsed (the value we want to find)

On the other hand, we are told the current amount of Carbon-14 A  is 19\%=0.19, assuming the initial amount of Carbon-14 A_{o}= is  100\%:

A=0.19A_{o} (2)

This means: \frac{A}{A_{o}}=0.19 (2)

Now,finding t from (1):

\frac{A}{A_{o}}=e^{-0.0001211.t}  (3)

Applying natural logarithm on both sides:

ln(\frac{A}{A_{o}})=ln(e^{-0.0001211.t})  (4)

ln(0.19)=-0.0001211.t  (5)

t=\frac{ln(0.19)}{-0.0001211}  (6)

Finally:

t=13713.717years  This is the age of the paintings and the option that is nearest to this value is C. 13839 years

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