Answer:
25%
Explanation:
The female with brown teeth had a father with normal teeth. Since normal teeth is a recessive trait, the father would have been homozygous recessive for the trait and would have transmitted one recessive allele to the female. Therefore, the female is heterozygous dominant for brown teeth.
Let's assume that the allele for brown teeth is X^B while the one for normal teeth is X^b. The genotype of heterozygous dominant female would be X^BX^b and that of the male with normal teeth would be X^bY.
A cross between X^BX^b and X^bY gives progeny in following phenotype ratio= 1/4 daughter with brown teeth: 1/4 daughter with normal teeth: 1/4 son with brown teeth: 1/4 son with normal teeth. Therefore, the probability of having a daughter with brown teeth is = 25%
The correct answer is c i believe
<span>The answer is logistic.In this types of growth, the population growth slows as it reaches carrying capacity. This is when there are increased competition for limited resources, between individuals in the population, in the environment. This slow rate of reproduction also occurs in type I survivorship curves</span>
Answer:
Resting potential
Explanation:
This is because , the resting potential is negative in side of the cell because it has more negative charge inside than outside due to accumulation of alot of sodium and potassium ions. when an axon is at rest in the cell, the anions produce negative charge, the sodium pumps eject sodium out of the cell and potassium is injected in, and the sodium gates and potassium gates are all closed.