Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D)
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
Given:
The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).
To find:
The area of the rectangle.
Solution:
Distance formula:
Using the distance formula, we get
Similarly,
Now, the length of the rectangle is and the width of the rectangle is . So, the area of the rectangle is:
Therefore, the area of the rectangle is 20 square units.
Answer:
https://demo.tds.cambiumast.com/DesmosForAssessments/TDSCalculator.html?mode=fl_scirestricted
Step-by-step explanation:
-4.08 is greater than -4.7 since its negative
ex: -1 is greater than -2 since -1 is closer to zero than -2
24 tiles
you take 2 yards and 3 yards and multiple them together getting 6 yards, then convert yards to feet resulting in 18 feet, divide that by 1.5 ft and you get 24 tiles.
