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Ilya [14]
2 years ago
15

A new science website has $1824 to buy online ads. If each cost $96, how many ads can the website purchase

Mathematics
1 answer:
a_sh-v [17]2 years ago
3 0

Answer:

19 ads

Step-by-step explanation:

just divide 1824 by 96

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Is the long haired cat in the p generation a hybrid or pure bread explain your answer
Levart [38]
The long haired cat p generation is a hybrid because the hair is long and that is not the pure so the answer is hybrid.
8 0
3 years ago
How does writing 3.441 in expanded form show why the same digit can have different values?
Olegator [25]
<span>Answer:
Standard Form:

3.441

<span>Expanded forms can be written
like a sentence or stacked for
readability as they are here.</span>

Expanded Numbers Form:

<span><span> 3 </span><span>+ 0.4</span><span>+ 0.04</span><span>+ 0.001</span></span>
Expanded Factors Form:

<span><span> 3 ×1 </span><span>+4 × 0.1</span><span>+4 × 0.01</span><span>+1 × 0.001</span></span>
Expanded Exponential Form:

<span><span>3 × 100</span><span>+<span>4 × 10-1</span></span><span>+<span>4 × 10-2</span></span><span>+<span>1 × 10-3</span></span></span>
Word Form:

three and
four hundred forty-one thousandths

</span>
3 0
3 years ago
Read 2 more answers
Fie O centrul unui cerc si doua unghiuri la centru adiacente AOB si BOC.Stiind ca masura unghiului AOB = 120 si masura BOC= 150,
kodGreya [7K]

<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution

Given the above information;
AC=AB, therefore ABC is an isosceles triangle. 
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60


4 0
3 years ago
The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te
kozerog [31]

Answer:

\dfrac{6}{7}.

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

a_n=ar^{n-1}

a+ar=6     ...(1)

Each term is 5 times the sum of the succeeding terms.

a_n=5(a_{n+1}+a_{n+2}+...+\infty)

ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)

ar^{n-1}=5ar^n(1+r+r^2+...+\infty)

Divide both sides by a.

r^{n-1}=5r^n(\dfrac{1}{1-r})    [\text{Sum of infinite GP}=\dfrac{a}{1-r}]

\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}

\dfrac{1}{r}=\dfrac{5}{1-r}

1-r=5r

1=6r

\dfrac{1}{6}=r

The common ratio is 1/6.

Put r=1/6 in (1).

a+a(\dfrac{1}{6})=6

6a+a=36

7a=36

a=\dfrac{36}{7}

Second term ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}

Therefore, the second term is \dfrac{6}{7}.

4 0
3 years ago
What is the length of EF in the right triangle below? 25 7
Leno4ka [110]

Answer:

The answer is 185

Step-by-step explanation:

25 times 7 =185

4 0
1 year ago
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