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Ilya [14]
2 years ago
15

A new science website has $1824 to buy online ads. If each cost $96, how many ads can the website purchase

Mathematics
1 answer:
a_sh-v [17]2 years ago
3 0

Answer:

19 ads

Step-by-step explanation:

just divide 1824 by 96

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A. Write 60,000,000 in words.
Vitek1552 [10]

Answer:

The answer is sixty million.

5 0
2 years ago
Which is the best estimate of the measure of this angle?
Pani-rosa [81]

Answer:

That angle looks like a reflex angle

Step-by-step explanation:

I think D is the answer, since Reflex angles are ALWAYS be more than 180 and less than 360

I hope this helps! So srry if its wrong

5 0
1 year ago
Find all solutions to the equation. 2sin theta - squareroot 3 = 0
Xelga [282]

Answer:

\theta =2mπ + π/3 for m ∈ Z.

Step-by-step explanation:

Given the equation 2sin\theta - \sqrt{3} = 0, we are to find all the values of \theta that satisfies the equation.

2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0

General solution for sin\theta is \theta = nπ + (-1)ⁿ ∝, where n ∈ Z.

If n is an even number say 2m, then \theta = (2m)π + ∝ where ∝ = 60° = π/3

Hence, the general solution to the equation will be \theta = 2mπ + π/3 for m ∈ Z.

8 0
3 years ago
Oscar is landscaping his yard. He is putting mulch in the flower beds to help minimize weeds. He has 4 1/4 bags of mulch in his
Rzqust [24]

Answer:

c) 300.9 ft²

Step-by-step explanation:

He has 4 1/4 bags of mulch in his shed to use. Each bag of mulch will cover 70.8 ft².

Hence:

1 bag of mulch = 70.8ft²

4 1/4 bags of mulch = x ft²

Cross Multiply

1 bag × x ft² = 4 1/4 × 70.8

x ft² = 4 1/4 × 70.8/1

x = 300.9 ft²

Option c is correct.

7 0
3 years ago
‼️‼️Help anyone ‼️‼️‼️
Debora [2.8K]
Method 1
You can use <span>The equilateral triangle </span>(look at the picture)
\dfrac{a\sqrt3}{2}=1\ \ \ \cdot2\\\\a\sqrt3=2\ \ \ |\cdot\sqrt3\\\\3a=2\sqrt3\ \ \ |:3\\\\a=\dfrac{2\sqrt3}{3}\\\\\boxed{|AC|=\dfrac{2\sqrt3}{3}}


Method 2
You can use the <span>trigonometric function</span>
\sin60^o=\dfrac{1}{|AC|}\\\\\sin60^o=\dfrac{\sqrt3}{2}\\\\\dfrac{1}{|AC|}=\dfrac{\sqrt3}{2}\ \ \ |\cross\ multiply\\\\|AC|\sqrt3=2\ \ \ |\cdot\sqrt3\\\\3|AC|=2\sqrt3\ \ \ \ |:3\\\\\boxed{|AC|=\dfrac{2\sqrt3}{3}}
<span />

4 0
3 years ago
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