Answer: A) y=-1/2x+1
Step-by-step explanation:
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
Try this:
x³+4x²+x-6=0
1) To re-write the equation into form:
1*x³+4*x²+1*x-6=0, the note 1+4+1=6, it means x=1
2) to re-write the equation into form:
(x-1)(x²+5x+6)=0
(x-1)(x+2)(x+3)=0
3)
Answer: -3;-2;1.
Standard equation for a circle is: (x -h)² + (y - k)² = r²
(h,k) is the center which is given to be: (0,0) so you just need the radius.
The radius is the distance from the center to the point (-4,5) on the edge.
Use the distance formula
d = √[(-4 - 0)² + (5 -0)²]
d = √[16 + 25]
d = √[41]
radius is √[41]
so the equation for the circle is: x² + y² = 41