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3 years ago

A bullet of mass 20g is horizontally fired with a velocity of 150m/s from a pistol of mass 2 kg. What is the

Physics

1 answer:

kiruha [24]3 years ago

7 0

Answer:

m1 = 20g (= 0.02 kg)

Mass of pistol, m2 = 2 kg

Initial velocity of the bullet (u1) and pistol (u2) = 0

Final velocity of the bullet, v1 = +150m s-1

Let v be the recoil velocity of the pistol.

Total momentum of the pistol and bullet after it is fired is

= (0.02 kg x 150 m s-1) + (2 kg x v m s-1)

= (3 + 2v) kg m s-1

Total momentum after the fire = Total momentum before the fire

3 + 2v = 0

→v = -1.5 m/s

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What do astonomers use to calculate the age of the universe

makvit [3.9K]

Answer: Stars

Explanation: Some stars have remained intact since the Big Bang. These stars are shown in something called the HR diagram with portrays the brightness and largeness of the star. Also, white dwarfs and black dwarfs can be traced back which may correspond with the initiation of the universe.

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3 years ago

Guys I really need help with these 2 questions , it's for my final plz help asap

mars1129 [50]

Answer:

(1) Initial speed, $u=0$

Final speed, $v=165.76m/s$

Average speed, $v_a_v_g=82.87m/s$

(2) Force of gravity, $F_g=12.8\times10^1^5N$

Explanation:

(1)

Given,

Distance, $S=300meter$

Time, $t=3.62second$

It is given that drag racer started at rest.

So Initial speed, $u=0$

Using Newton's second equation of motion,

$S=ut+\frac{1}{2}at^2\\300=0+\frac{a\times3.62^2}{2} \\a=45.79m/s^2$

Newton's first equation of motion,

$v=u+at\\=0+45.79\times3.62\\=165.76 m/s$

So, Final speed, $v=165.76m/s$

Average speed is defined as totle distance divided by totle time.

$v_a_v_g=\frac{S}{t}\\=\frac{300}{3.62} \\=82.87m/s$

So, Average speed, $v_a_v_g=82.87m/s$

(2)

Gravitation: It is the natural phenomenon in which two different bodies attract each other by virtue of their masses.

According to Newton's law of gravitation, the force of attraction between two bodies is directly proportional to the masses of the bodies and inversely proportional to square of distance between centers of mass of the bodies.

$F_g\propto\frac{m_1m_2}{r^2} \\F_g=G\frac{m_1m_2}{r^2}$ where $G$ is constant of proportionality and known as gravitation constant.

Given,

Mass of Jupiter, $m_1=1.9\times10^2^7kg$

Mass of Ganymede, $m_2=1.48\times10^2^3kg$

Distance between their centers of mass, $r=1.21\times10^1^2meter$

$F_g=G\frac{m_1m_2}{r^2}\\=\frac{6.67\times10^-^1^1\times1.9\times10^2^7\times1.48\times10^2^3}{(1.21\times10^1^2)^2} \\=12.8\times10^1^5N$

So, Force of gravity, $F_g=12.8\times10^1^5N$

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3 years ago

Each milligram of glucose has the same amount of energy available to do work. The series B test tubes produced more bacteria per

yKpoI14uk [10]

Answer:

The series A test tube has some left amount of glucose left in it.

Explanation:

Let's assume that a fixed amount of glucose is synthesized, for the fixed quantity the bacteria produced in A and B be x and y respectively,

Therefore, the condition on x and y is, y > x as the no. of bacteria present in B is greater.

As a result B would require a greater amount of energy for its functioning, these energy would be derived from the already fixed amount of glucose present.

A test tube would also require the energy for its x number of bacteria, but it is less than that of B.

Therefore, there would be some unused glucose left in Test Tube Series A which has unused energy.

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3 years ago

What is the inverse square law and how does it relate to gravity?

Nesterboy [21]

Answer:

Inverse Square Law Newton proposed the Inverse Square Law. The effect of gravity (and also on forces such as sunlight) works like this. If say we have a half-mass Earth, it would produce a gravity of not half but a quarter (the square of 2).

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4 years ago

If an engine cannot be 100%

geniusboy [140]

Answer: Given the evidence in the explanation, I'm pretty sure it's C. It still exists, but in a different form.

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3 years ago

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