Weight is equal to the mass of the object times the acceleration due to gravity (which is 9.8
on earth)
So W=mg
W=10.0 × 9.8 = 98
So the weight is 98N.
So W=mg
W=10.0 × 9.8 = 98
So the weight is 98N.
Where in your house do you find radio waves
2 answers:
You might be interested in
Answer:
1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km
2) Mia's average speed is 6.00 km/hour
Peter's average speed is 8.48 km/hour
4) Mia's average velocity = Peter's average velocity = 6.00 km/hour
Explanation:
The given information from the diagram are;
The distance Peter jogs from school to the flower shop = 2.00 km
The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.
The distance Mia walks from school directly to the Coffee shop = 3.00 km
The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour
1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km
The distance Mia travels from school to the Coffee shop = 3.00 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km
The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km
2)
Mia's average speed = 6.00 km/hour
Peter's average speed = 8.48 km/hour
4)
The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter
The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour
Mia's average velocity = 6.00 km/hour
Therefore, Peter's average velocity is also = 6.00 km/hour
Answer:
C. 500 watts
Explanation:
power is defined as the rate of work done
When a force causes a object to move, work is being done on the object by the force.
Answer:
The circus performer falls back down to the ground
Explanation:
The question parameters are;
The initial velocity of the circus performer = 21 m/s
The angle in which the performer launches himself = 75° towards the platform
The height of the platform above the ground = 20 m
The horizontal distance of the platform from the springboard = 15 m
The vertical motion of the circus performer is given by the following projectile motion relation;
y = y₀ + v₀·sinθ₀t-1/2·g·t²
Where;
y = Height reached by the circus performer
y₀ = Initial height of the the circus performer (the springboard) = 0 m
v₀ = Initial velocity of the the circus performer = 21 m/s
θ₀ = The angle with which the circus performer launches himself = 75°
t = The time of ,light of the circus performer
g = The acceleration due to gravity
Therefore, when the height is 20 m, we have;
20 = 21*sin(75)*t - 1/2*9.81*t²
Which gives;
21*sin(75)*t - 1/2*9.81*t² - 20 = 0
Factorizing using a graphing calculator, gives;
t = 1.623 or t = 2.513
Therefore, the circus performer passes the 20 m mark twice, in his motion, where the first time is when he is on his way up while the second time is when he is on his way down
The horizontal motion of the circus performer is given by the following projectile motion relation;
x = x₀ + v₀*cos(θ₀)* t
Where;
x₀ = The initial position of the circus performer in relation to the final position = 0
Plugging in the value of t when y = 20, we get;
x = 21×cos(75)×1.623 = 8.82 m, which is less than the 15 m platform distance from the spring board
Checking the other time value, we have;
x = 21×cos(75)×2.513 = 13.66 m which is also less than the 15 m platform distance from the spring board
Therefore, the circus performer misses the platform and falls back down to the ground.
You would make rings of clay and then place the beads on the rings (one on each) at various places and one in the center for the nucleus.
