Based on the values of E, C, and R, the maximum charge on the capacitor can be found to be 1.80 x 10⁻⁴ C.
<h3>What is the maximum charge?</h3>
The maximum charge on the capacitor can be found as:
= C x ( 10⁻⁶ / 1 μF) x E
Solving gives:
= 20.0 x ( 10⁻⁶ / 1 μF) x 9.00
= 1.80 x 10⁻⁴ C
In conclusion, the maximum charge is 1.80 x 10⁻⁴ C
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Answer:
0.00050, 0.000000000406, 36513
Answer:
14.7 m/sec.
Explanation:
We will go about using the mathematical formula,
Vf - Vo = gT.
To break it down,
Vf = Velocity of the apple just before hitting the ground.
Vo = Initial velocity of apple = 0
T = Time for apple to hit the ground = 1.5 sec
g = Acceleration due to gravity = 9.8 m/sec^2
We then need to substitute appropriate values,
<em>Vf - 0 = 9.8(1.5) </em>
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<em>Vf = 14.7 m/sec. </em>
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