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AURORKA [14]
3 years ago
9

How much kinetic energy does a 0.30-kg stone have if it is thrown at 44 m/s?

Physics
2 answers:
horrorfan [7]3 years ago
6 0

Answer:

0 290

Explanation:

ikadub [295]3 years ago
6 0

Answer:

290

Explanation:

the reason is that the formula for kinetic energy is half m×v².

you divde half by 0.30 multiply by 44×44

you get 290.4

then you round it to significant figures to get 290

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W = mg,      Assuming g ≈ 9.8 m/s² on the earth surface.

735 N =  m* 9.8

735/9.8 =  m

75 = m

Mass , m = 75 kg.  B.
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usted / el partido de fútbol Usted va al partido de fútbol. Question 1 with 1 blankyo / la biblioteca Question 2 with 1 blanknos
34kurt

Answer:

1- Yo VOY A la biblioteca

2- Nosotros VAMOS A la piscina

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5- Ustedes VAN AL parque municipal

6- Alejandro VA AL museo de ciencias

Explanation:

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Yo voy, el va, tú vas, nosotros vamos, ellos van, ustedes van

Así, debe interpretarse la persona o personas que realizan la acción, para determinar así como se conjuga dicho verbo.

4 0
3 years ago
Which statement describes the interaction between the north and south poles of two magnets?(1 point)
miskamm [114]

Answer:

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Explanation:

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5 0
2 years ago
Thermal conductivity of a material is given as 129Btuft–¹ h–¹°F–¹.Calculate this thermal conductivity in Jm–¹s–¹°C–¹(Given: 1Btu
ss7ja [257]

Answer:

223.25 $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$

Explanation:

The thermal conductivity of an object is defined as the measure or the ability of the object to transfer heat or conduct heat through its body.

In the context, the thermal conductivity of the material is given as

$=129 \text{ Btu ft}^{-1}\text{h}^{-1}^\circ\text{F}^{-1}$

And it is given that :

1 Btu = 1055 J

1 ft = 0.3048 m

$1^\circ F = \frac{5}{9}^\circ C$

We know that 1 h = 3600 s

So the thermal conductivity of the material in $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$ is  :

Thermal conductivity :

$=\frac{129 \text{ Btu}}{1 \text{ ft }\times \text{1 h}\times 1^\circ\text{F}}$

$=\frac{129 \times 1055 \text{ J}}{0.3048 \text{ m} \ \times 3600 \text{ s}\ \times \frac{5}{9}^\circ \text{C}}$

=  223.25 $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$

3 0
3 years ago
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