Which acid dissociation constant (ka indicates the weakest acid? 8.5 × 10–3m 1.5 × 10–10m 3.5 × 10–7m 5.1 × 10–5m?

1 answer:

7 0

Answer is: the weakest acid is with Ka = 1.5 × 10⁻¹⁰ M.
Ka is the acid dissociation constant, which quantifies the extent of acid dissociation in water.
The lower is the acid dissociation constant, the weaker is the acid, because concentration of hydrogen ions (H⁺) or hydronium ions (H₃O⁺) is very low.
For some acid, chemical reaction in water: HA(aq) ⇄ A⁻(aq) + H⁺(aq), acid dissociation constant is: Ka = [A⁻]·[H⁺] / [HA].

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According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?

saul85 [17]

Answer:

1.935 mole

Explanation:

We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.

Now if 1 mole of N2 contains 6.02x10^23 molecules,

Then Xmol of N2 will contain 3.88x10^23 molecules i.e

Xmol of N2 = (3.88x10^23)/6.02x10^23

Xmol of N2 = 0.645 mole

Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:

The equation for the reaction is given below:

3PbO + 2NH3 → 3Pb + N2 + 3H2O

From the balanced equation above, 3 moles of PbO produced 1 mole of N2.

Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e

Xmol of PbO = 3 x 0.645

Xmol of PbO = 1.935 mole.

From the calculations made above,

1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).

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Definition of steepest

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Hi, friend.
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