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3 years ago

Matter that has a definite shape and value

Chemistry

1 answer:

KonstantinChe [14]3 years ago

6 0

Answer:

Matter has a definite shape and volume in it's solid form. In liquid form, the shape of matter can change e.g. water. In gas form, there is no definite shape, neither volume.

Explanation:

I think that you meant volume instead of value. I hope this answers your question!

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How many molecules are in 0.25 moles of CH4

Brums [2.3K]

The base gram of the compound is 16.042

To find the new amount of grams, you need to multiply the amount of moles by the the base grams

16.042*.25=4.01

So one fourth of the compound is 4.01 grams of Carbon tetrahydride.

6 0

3 years ago

Of the following gases, ________ will have the greatest rate of effusion at a given temperature. Of the following gases, _______

kolezko [41]

Answer: From the given gases, the greatest rate of effusion is of $CH_4$

Explanation:

Rate of effusion of a gas is determined by a law known as Graham's Law.

This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.

For the given gases:

Molar mass of $NH_3=17g/mol$

Molar mass of $HCl=36.5g/mol$

Molar mass of $CH_4=16g/mol$

Molar mass of $Ar=40g/mol$

Molar mass of $HBr=81g/mol$

The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.

Hence, the greatest rate of effusion is of $CH_4$

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4 years ago

Diazene, N2H2 (also known as diimine), is commonly used as a reagent for organic syntheses. Label each image with the type of

Fittoniya [83]

The first image shown at the left hand side is a pi bond. The other two images show sigma bonds.

In chemistry, a bond results from the overlap of atomic orbitals. This overlap may be end to end (sigma bond) or side by side (pi bond). Having said this, it is easier to decide whether the bonds in the image shown are sigma or bi bonds.

If we label the images; 1,2,3 from left to right, we can see that the overlap in image 1 is side by side. The electron density lies above and below the plane of the bond. This is a pi bond. In images 2 and 3, the overlap occurs in an end to end manner. This is a sigma bond.

Learn more: brainly.com/question/14018074

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2 years ago

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Answer:

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