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liberstina [14]
3 years ago
5

The picture below shows one cell dividing into two cells.

Chemistry
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

All cells come from pre existing cells.

Explanation:

vitfil [10]3 years ago
4 0

all cells come from pre existing cells


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If 1.0 mole of CH4 and 2.0 moles of Cl2 are used in the reaction CH4 + 4Cl2 => CCl4 + 4HCl then which of these statements is
nikklg [1K]

Answer:

B,C,D

Explanation:

The yield of CCl4 depends on the amount of CH4 in a 1:1 ratio. The amount of Cl2 is twice that of CH4 hence some must be left over. To ensure that all the Cl2 is used up, more CH4 must added to the system.

4 0
3 years ago
How is n1 in the Rydberg equation related to the quantum number n in the Bohr model of the atom?
ad-work [718]

Explanation:

The n in Bohr model of the atom is principle quantum number.

The Rydberg n integer stats represent electron orbits at various integral distances from the atom in Bohr's conceptualization of the atom. Subsequent models discovered that the values for n1 and n2 match the two orbitals ' principle quantum numbers.

8 0
4 years ago
What information about a molecule can you determine from its<br> chemical formula?
Ira Lisetskai [31]

Answer:

Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the number of atoms of each element present in each molecule is shown as a subscript following that element's symbol.

6 0
3 years ago
A 1.547 g sample of blue copper(II) sulfate pentahydrate, ‍ , is heated carefully to drive off the water. The white crystals of
sweet [91]

Answer:

=6.2x10^{-3}mol CuSO_4

Explanation:

Hello,

By developing the following stoichiometric relationship, the required amount could be found as follows:

- Moles of CuSO_4:

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{1mol CuSO_4}{1mol CuSO_4.5H_2O} =6.2x10^{-3}mol CuSO_4

- Grams of CuSO_4

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{1mol CuSO_4}{1mol CuSO_4.5H_2O}*\frac{159.5g CuSO_4}{1mol CuSO_4} =0.989 g CuSO_4

- Moles of water:

1.547gCuSO_4.5H_2O *\frac{1molCuSO_4.5H_2O}{249.5gCuSO_4.5H_2O} *\frac{5mol H_2O}{1mol CuSO_4.5H_2O}=0.031mol H_2O

Finally, one could see that the mass of the anhydrous compound is less than the pentahydrated compound since it is waterless.

Best regards.

8 0
3 years ago
What happens to that atom of magnesium-24 if it GAINS a NEUTRON? *
kipiarov [429]

Answer:  If this atom loses one electron, it will become a cation with a 1+ charge

Explanation:

4 0
3 years ago
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