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liberstina [14]
3 years ago
5

The picture below shows one cell dividing into two cells.

Chemistry
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

All cells come from pre existing cells.

Explanation:

vitfil [10]3 years ago
4 0

all cells come from pre existing cells


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What is the velocity of a electron whose wavelength is 100 pm?
Anni [7]

Answer:

v = 7.3 × 10⁶ m/s

Explanation:

Given data:

Velocity of electron = ?

Wavelength = 100 pm

Solution:

Formula:

λ = h/mv

λ = wavelength

h = planck's constant

m = mass

v = velocity

Now we will put the values in formula.

100 ×10⁻¹² m = 6.63 × 10⁻³⁴ j.s / 9.109 × 10⁻³¹ kg ×  v

v = 6.63 × 10⁻³⁴ kg.m²/s /  9.109 × 10⁻³¹ kg ×100 ×10⁻¹² m

v = 6.63 × 10⁻³⁴ m/s /910.9 × 10⁻⁴³

v = 0.0073  × 10⁹ m/s

v = 7.3 × 10⁶ m/s

5 0
3 years ago
Need help setting the problem up
Sveta_85 [38]

Answer:

4.0 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 12L

Pressure = 5.6 atm

Temperature (T) = 205K

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

PV = nRT

5.6 x 12 = n x 0.08206 x 205

Divide both side by 0.08206 x 205

n = (5.6 x 12)/(0.08206 x 205)

n = 4.0 moles

Therefore, the number of mole of the gas is 4.0 moles

5 0
3 years ago
Choose all the answers that apply.
Arada [10]

Answer:

removing topsoil

Explanation:

5 0
3 years ago
Read 2 more answers
The density of aluminum is 2.7 g/ml what is the volume of 8.1 g
Nikolay [14]
D = m / V

2.7 = 8.1 / V

V = 8.1 / 2.7

V = 3.0 mL
8 0
3 years ago
Read 2 more answers
Using the following equation for the combustion of octane, calculate the heat associated with the formation of 100.0 g of carbon
givi [52]

Answer: Heat associated with the formation of 100.0 g of carbon dioxide is 1563.2 kJ.

Explanation:

Reaction equation will be as follows.

    2C_{8}H_{18} + 25O_{2} \rightarrow 16CO_{2} + 18H_{2}O;  \Delta H^{o}_{rxn} = -11018 kJ

Mass of CO_{2} = 100 g

Hence, moles of CO_{2} present will be calculated as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{100 g}{44.0095 g/mol}

                             = 2.27 mol

Therefore, heat produced by 2.27 mol for the given reaction will be calculated as follows.

         2.27 mol \times \frac{11018 kJ}{16 mol CO_{2}}

             = 1563.2 kJ

Thus, we can conclude that heat associated with the formation of 100.0 g of carbon dioxide is 1563.2 kJ.

7 0
3 years ago
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