The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.
The graph is attached below.
- We are given a quadratic function.
- A polynomial equation of degree two in one variable is a quadratic equation.
- The function given to us is :
- y = x² - 5x - 36
- We need to find the solution of the quadratic function.
- To find the roots, let y = 0.
- x² - 5x - 36 = 0
- Use the quadratic formula.
- In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
- x = [-b±√b²-4ac]/2a
- x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
- x = (5 ± √25 + 144)/2
- x = (5 ± √169)/2
- x = (5 ± 13)/2
- x = 9 or x = -4
To learn more about functions, visit :
brainly.com/question/12431044
#SPJ1
1 gallon of water= 3.79 liters of water
1 liter of water makes 4 1/3 glasses of water
Answer:
AAS is an acronym for Angle-Angle-Side. It basically means that if two angles and a nonincluded side of one triangle are congruent to two angles and the corresponding nonincluded side of a second triangle, then the two triangles are congruent. SAS is an acronym for Side-Angle-Side. It means that if two sides and the included angle of one triangle are congruent to two sides and the included angle of a second triangle, then the two triangles are congruent. SSS is an acronym for Side-Side-Side. It means that if three sides of one triangle are congruent to three sides of a second triangle, then the two triangles are congruent. ASA is an acronym for Angle-Side-Angle. It means that if two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the two triangles are congruent.
In the problem, we know that the corresponding sides of both triangles are congruent to each other, so those would be given. The third side of each triangle would also be congruent because of reflexive property. Reflexive property means that the two triangles share a line segment. So, the answer would be SSS.
d1 = 51(t)
d2 = 71(8 - t)
d1 + d2 = 508
and now you just have to solve for t.
