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3 years ago

Nicole is playing a video game where each round lasts

Mathematics

2 answers:

sammy [17]3 years ago

5 0

The following steps will help you find how many rounds Nicole can play in 3 $\frac{3}{4}$ hours.

STEP 1:
Convert 3 $\frac{3}{4}$ into a mixed number.
3 $\frac{3}{4}$ = $\frac{15}{4}$

STEP 2:
You now need to divide $\frac{15}{4}$ by $\frac{3}{4}$ = 5 rounds
So,
Nicole can play for 5 rounds in 3 hours and $\frac{3}{4} th$ of an hour.

77julia77 [94]3 years ago

3 0

15/4times 4/3= 60/12=5
Answer 5

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A group of friends wants to go to the amusement park. They have $135.50 to spend on parking and admission. Parking is $8.50, and

sergejj [24]

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6 0

2 years ago

A large cable company reports the following:

Step2247 [10]

Answer:

$P(Cable\ TV\ only) = 50\%$

$P(Internet\ |\ cable\ TV) = 31.25\%$

$P(exactly\ 2\ services) = 23\%$

$P(Internet\ and\ cable\ TV \only) = 23\%$

Step-by-step explanation:

Given

$Cable\ TV = 80\%$

$Internet = 44\%$

$Telephone = 29\%$

$Cable\ TV\ and\ Internet = 25\%$

$Cable\ TV\ and\ Telephone = 20\%$

$Internet\ and\ Telephone = 23\%$

$All\ Services = 15\%$

Solving (a): A) P(cable TV only).

First, we calculate n(cable TV only)

This is calculated as:

$n(cable\ TV\ only) = (Cable\ TV) - (Cable\ TV\ and\ Internet) - (Cable\ TV\ and\ Telephone) + (All\ Services)$

$n(cable\ TV\ only) = 80\% - 25\% - 20\% + 15\%$

$n(cable\ TV\ only) = 50\%$

The probability is:

$P(Cable\ TV\ only) = \frac{n(Cable\ TV\ only)}{100\%}$

$P(Cable\ TV\ only) = \frac{50\%}{100\%}$

$P(Cable\ TV\ only) = 50\%$

Solving (b): P(Internet | cable TV).

This is calculated as:

$P(Internet\ |\ cable\ TV) = \frac{Cable\ TV\ and\ Internet}{Cable\ TV}$

$P(Internet\ |\ cable\ TV) = \frac{25\%}{80\%}$

$P(Internet\ |\ cable\ TV) = \frac{25}{80}$

$P(Internet\ |\ cable\ TV) = 31.25\%$

Solving (c): P(exactly 2 services).

This is calculated as:

$P(exactly\ 2\ services) = (Cable\ TV\ and\ Internet - All) + (Cable\ TV\ and\ Telephone - All) + (Internet\ and\ Telephone - All)$

$P(exactly\ 2\ services) = (25\% - 15\%) + (20\% - 15\%) + (23\%-15\%)$

$P(exactly\ 2\ services) = (10\%) + (5\%) + (8\%)$

$P(exactly\ 2\ services) = 23\%$

Solving (d): P(Internet and cable TV only).

This is calculated as:

$P(Internet\ and\ cable\ TV \only) = \frac{(Internet\ and\ cable\ TV \only)}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{1}$

$P(Internet\ and\ cable\ TV \only) = 23\%$

4 0

3 years ago

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Art [367]

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8 0

3 years ago

jane runs each lap in 7 minutes. she will run more than 56 minutes today. what are the possible numbers of laps she will run tod

trasher [3.6K]

Is she runs each lap in 7 min then 56 min you would divide it so 56/7=8

4 0

3 years ago

Use the quadratic formula to solve. Round to the nearest tenth if necessary. 2x^2 -3x -7 = 0

abruzzese [7]

The quadratic formula is:

$\frac{-b + \sqrt{b^2 - 4ac} }{2a}$ and $\frac{-b - \sqrt{b^2 - 4ac} }{2a}$