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ira [324]
3 years ago
11

1. Seekor burung helang berada 4.56 m di atas aras laut manakala seekor kuda laut berada 6.82 m

Mathematics
1 answer:
s2008m [1.1K]3 years ago
6 0

(a) Calculate the vertical distance between the eagle and the seahorse.

Answer a: 11.38 meters is the vertical distance between them.

(b) Describe Adrian's position from the sea level.

Answer b: Adrian is 1.13m below the sea level.

Step-by-step explanation:

(a) Since sea level is the origin of coordinates. distances above sea level are positive and distances below sea level are negative. The distance between two points is the difference between them.

The vertical distance between the eagle and the seahorse is the difference between their positions:  

Distance = 4.56m - (-6.82m) = 4.56m + 6.82m = 11.38 meters

Answer a) 11.38 meters is the vertical distance between them.

(b) Adrian's position is in the middle of the distance between the eagle and the seahorse:

Middle = 11.38m/2 = 5.69m

Since 5.69m is more than 4.56m above the sea level, then Adrian is below the sea level:

4.56m - 5.69m = -1.13m

Answer b: Adrian is 1.13m below the sea level.

<h2><em>Spymore</em></h2>

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X/33=-2/3i don't know how to solve this some one help me please
Delvig [45]

Answer:

x/i=22

Step-by-step explanation:

x/33=2/3*i

*33       *33

x=2/3*33*i

/i              /i

x/i=2/3*33

x/i=22

6 0
2 years ago
I need help with questions #7 and #8 plz
katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

c^2 = a^2 + b^2 - 2ab \cos C

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

18^2 = 12^2 + 16^2 - 2(12)(16) \cos C

324 = 144 + 256 - 384 \cos C

-384 \cos C = -76

\cos C = 0.2

C = \cos^{-1} 0.2

C = 78.6^\circ

Now we use the law of sines to find angle A.

Law of Sines

\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

We know c and C. We can solve for a.

\dfrac{a}{\sin A} = \dfrac{c}{\sin C}

\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}

Cross multiply.

18 \sin A = 12 \sin 78.6^\circ

\sin A = \dfrac{12 \sin 78.6^\circ}{18}

\sin A = 0.6535

A = \sin^{-1} 0.6535

A = 40.8^\circ

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

a^2 = b^2 + c^2 - 2bc \cos A

b^2 = a^2 + c^2 - 2ac \cos B

c^2 = a^2 + b^2 - 2ab \cos C

Find angle A:

a^2 = b^2 + c^2 - 2bc \cos A

8^2 = 18^2 + 12^2 - 2(18)(12) \cos A

64 = 468 - 432 \cos A

\cos A = 0.9352

A = 20.7^\circ

Find angle B:

b^2 = a^2 + c^2 - 2ac \cos B

18^2 = 8^2 + 12^2 - 2(8)(12) \cos B

324 = 208 - 192 \cos A

\cos B = -0.6042

B = 127.2^\circ

Find angle C:

c^2 = a^2 + b^2 - 2ab \cos C

12^2 = 8^2 + 18^2 - 2(8)(18) \cos B

144 = 388 - 288 \cos A

\cos C = 0.8472

C = 32.1^\circ

8 0
2 years ago
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seropon [69]

Answer:

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Step-by-step explanation:

If u multiply 24 x4 it is 96 and when I multiply 12x4 is 48 and u add 96 plus 48 u get 144.

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