Hello, It is very simples.
Look it :
Let a^3 - b^3 = ?
Add on both th side -3a^2b + 3ab^2
a^3 -3a^2b + 3ab^2 -b^3 = ?
-3a^2b+3ab^2
The firs equation is = (a - b)^3
Then,
(a - b)^3 = ? + 3a^2b - 3ab^2
Passing -3a^2b + 3ab^2 to the left side:
But changing the sinal
? = (a - b)^3 + 3a^2b - 3ab^2
? = (a - b)^3 + 3ab ( a - b)
Putting (a - b) as commun factor
? = (a - b).[ 3ab + (a - b)^2 ]
As (a - b)^2 = a^2 - 2ab + b^2
Then,
? = (a - b).[ 3ab + a^2 -2ab +b^2]
? = (a - b).( a^2 + ab + b^2)
I hope helps!
The answer to your question is [0, <span>∞)</span>
Only when any equation you find among those numbers can be simplified into one of the four main equations, wich means you only have four different true statements, and lots of equivalences.
Answer:
-8
Step-by-step explanation:
-4d=32
d=32/-4
d=-8
Answer:
Gavin uses more rope.
Step-by-step explanation:
Because 1/4>1/8, since 1/4=0.25 and 1/8=0.125.