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Sonbull [250]
3 years ago
15

Sherita has a mass of 50 kg and slowly climbs up a 5 m high flight of stairs how much work dose sherita do in ascending the stai

rs?
Physics
1 answer:
elixir [45]3 years ago
4 0
Work done = Mass * displacement 
W = 50 * 5 = 250 watts

In short, Your Answer would be 250 watts

Hope this helps!
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Two people start biking from the same point. One bikes east at 9 mph, the other south at 28 mph. What is the rate at which the d
Irina-Kira [14]

Answer:

(a) 31.75 mph

(b) 31.77 mph

Explanation:

(a) For t = 10 min = 10 / 60 = 1 / 6 hour

According to the question,

dx /dt = 15 mph

dy / dt = 28 mph

After 10 minutes

x = 1/6 x 15 = 2.5 miles

y = 1/6 x 28 = 4.67 miles

d = \sqrt{x^{2}+y^{2}}=\sqrt{2.5^{2}+4.67^{2}} = 5.3 miles

According to diagram

D^{2} = {x^{2}+y^{2}}

Differentiate both sides with respect to t.

2D dD/dt = 2 x dx/dt + 2y dy/dt

D dD/dt = x dx/dt + y dy/dt

5.3 dD/dt = 2.5 (15) + 4.67 (28)

dD/dt = 31.75 miles/hour

(b) For t = 55 minutes = 55 / 60 hours

After 55 / 60 hours

x = 55 / 60 (15) = 13.75 miles

y = 55 / 60 (28) = 25.67 miles

d = \sqrt{x^{2}+y^{2}}=\sqrt{13.75^{2}+25.67^{2}} = 29.12 miles

According to diagram

D^{2} = {x^{2}+y^{2}}

Differentiate both sides with respect to t.

2D dD/dt = 2 x dx/dt + 2y dy/dt

D dD/dt = x dx/dt + y dy/dt

29.12 dD/dt = 13.75 (15) + 25.67 (28)

dD/dt = 31.77 miles/hour

8 0
4 years ago
Two objects are connected by a string that passes over a frictionless pulley as in the figure below, where m1 < m2 and a1 and
Lady_Fox [76]

Answer:2

Explanation:

Given

m_2>m_1

and a_1 and a_2 are the acceleration of 1 and 2

Suppose  T is the Tension

then for block 2

m_2g-T=m_2a

m_2(g-a)=T---1

For block 1

T-m_1g=m_1a

T=m_1(g+a)----2

equate 1 and 2

m_2(g-a)=m_1(g+a)

a=\frac{m_2-m_1}{m_1+m_2}

where a=a_1=a_2

thus we can see that a is less than g

therefore a_2 < g

4 0
3 years ago
PLEASE HELP BRANILIEST
frozen [14]
Answer: It’s Fiberglass
5 0
3 years ago
Read 2 more answers
_____ provide a picture of an electric field indicating a field’s strength.Question 15 options:CapacitorsElectric potential diff
kaheart [24]

Electric field lines are a pictorial way to represent the electric field of a charge which basically indicates the field's strength.

The electric field is strong when the lines are close together and weak when they are far away from each other.

The greater the strength of the charge, the greater will be the number of field lines.

Hence, electric field lines provide a picture of an electric field indicating a field’s strength.

The correct option is Electric field lines

4 0
1 year ago
Letícia leaves the grocery store and walks 150.0 m to the parking lot. Then, she turns 90° to the right and walks an additional
Alexxx [7]

Answer:

165.529454

Explanation:

According to the Pythagorean Theorem for calculating the lengths of a right angle triangle's sides, a^2 + b+2 = c^2, where c is the longest side (and the side opposing the right angle). So in your case it would be 150*150 + 70*70 = 27400. And √ 27400 is your answer.

7 0
3 years ago
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