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faust18 [17]
1 year ago
7

_____ provide a picture of an electric field indicating a field’s strength.Question 15 options:CapacitorsElectric potential diff

erencesElectric fieldsElectric field lines
Physics
1 answer:
kaheart [24]1 year ago
4 0

Electric field lines are a pictorial way to represent the electric field of a charge which basically indicates the field's strength.

The electric field is strong when the lines are close together and weak when they are far away from each other.

The greater the strength of the charge, the greater will be the number of field lines.

Hence, electric field lines provide a picture of an electric field indicating a field’s strength.

The correct option is Electric field lines

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If a bullet travels at 551.0 m/s, what is its speed in miles per hour?
77julia77 [94]
<span>First, convert meters into feet. One meter = 3.28 feet. Next, convert meters per second to feet per second. 551.0 m/s = 1,807.28 ft/sec. Now using the knowledge that 5280 ft = 1 mile and there are 3600 seconds in an hour; convert 1,807.28 ft/sec into miles per hour. The final answer to the question is 1,232.24 miles per hour.</span>
6 0
3 years ago
What are five differences between drama and prose​
Romashka [77]

Answer:

Drama: it has sadness anger and romance

and

i forgot about Prose =w=

Explanation:

6 0
3 years ago
A spring has a length of .200 m when a .300 kg hangs from it,and a length of .750 m when a 1.95 kg hangs from it.what is the for
musickatia [10]

1) 29.5 N/m

2) 0.100 m

Explanation:

1)

The force constant of the spring can be found by using the fact that the force on the spring is proportional to the extension of the spring (Hooke's Law). Therefore, we can write:

\Delta F= k \Delta x

where

\Delta F = F_2 - F_1 is the change in the force on the spring, where

F_1 = m_1 g = (0.300)(9.8)=2.94 N is the force applied when the hanging mass is

m_1 = 0.300 kg

F_2 = m_2 g = (1.95)(9.8)=19.1 N is the force applied when the hanging mass is

m_2 = 1.95 kg

\Delta x=x_2 -x_1 is the change in extension of the spring, where

x_1=0.200 m is the extension of the spring when the hanging mass is 0.300 kg

x_2=0.750 m is the extension of the spring when the hanging mass is 1.95 kg

Solving for k,

k=\frac{F_2-F_1}{x_2-x_1}=\frac{19.1-2.94}{0.750-0.200}=29.5 N/m

2)

When the first mass is hanging on the spring, we have

F_1 = k (x_1 - x_0)

where:

F_1 is the force applied on the spring (the weight of the hanging mass)

k is the spring constant

x_1 is the extension of the spring wrt its natural length

x_0 is the natural length of the spring (the unloaded length)

Here we have

F_1=2.94 N

k = 29.5 N/m

x_1=0.200 m

Solving for x_0, we find:

x_0 = x_1 - \frac{F_1}{k}=0.200 - \frac{2.94}{29.5}=0.100 m

5 0
3 years ago
The value of gravitational acceleration of a body on earth is 9.8m/s^2. The gravitational potential energy for a 1.00 kilogram o
emmasim [6.3K]

Answer:

The object is 1.2755 meters above the ground

Explanation:

Recall the formula for gravitational potential energy for an object of mass "m" at a height "h" above the ground:

PE=m\,*\,g\,*\,h

In this case, since we are given the mass of the object and the object's potential energy, we can estimate the only unknown (height "h") from the formula shown above. Also since all units are given in the SI system, the result for the object's height will result in meters:

PE=m\,*\,g\,*\,h\\12.5\,J=1.0\,kg\,*9.8\,\frac{m}{s^2} \,*\,h\\\frac{12.5}{9.8} \,meters= h\\h=1.2755\ meters

4 0
3 years ago
What is newton's third law second law first law ?​
sergeinik [125]

Answer:

first law: an object remains in uniform motion except an external force has acted upon it eg a ball in stable motion doesn't move until one moves or kicks it

second law:the body acted upon by an external force gains a momentum which is directly proportional to the applied force and acts in the direction of the force

third law: to every action there is an equal and opposite reaction eg if u push someone the person moves backward away from you and not towards you

8 0
3 years ago
Read 2 more answers
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