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3 years ago

15

Which component of weight is cause for S.H.M of bob simple pendulum

1 answer:

jeka57 [31]3 years ago

6 0

Explanation:

The Simple Pendulum. A simple pendulum is defined to have a point mass, also known as the pendulum bob, which is suspended from a string of length L with negligible mass ((Figure)). Here, the only forces acting on the bob are the force of gravity (i.e., the weight of the bob) and tension from the string.

hope it helps you

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What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T ma

Sindrei [870]

Answer:

E = 1.50 × $10^{8}$ V/m

Explanation:

given data

B = 0.50 T

solution

we know that energy density by the magnetic field is express as

$\mu _b = \frac{B}{2\mu _o}$ ...............1

and

energy density due to electric filed is

$\mu _e = \frac{\epsilon _o E^2}{2}$ ...............2

and here $\mu _b = \mu _ e$

so that

E = $\frac{B}{\sqrt{\mu _o \times \epsilon _o}}$ ...................3

put here value and we get

$E = \frac{0.50}{\sqrt{4\pi \times 10^{-7} \times 8.852 \times 10^{-12}}}$

E = 3 × $10^{8}$ × 0.50

E = 1.50 × $10^{8}$ V/m

6 0

3 years ago

Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kg when weighed in air. The density of

sasho [114]

Answer:

m = 4.5021 kg

Explanation:

given,

Apparent mass of aluminium = 4.5 kg

density of air = 1.29 kg/m³

density of aluminium = 2.7 x 10⁷ kg/m³

true mass of the aluminium = ?

Weight in Vacuum

W = m g

W = ρV g

Air buoyancy acting on aluminium

B = ρ₀V g

Volume is the same in both cases since the volume of the aluminum

displaces an equal amount of volume air.

Apparent weight:

ρV g − ρ₀V g = 4.5 g

ρV − ρ₀V = 4.5

$V = \dfrac{4.5}{\rho - \rho_0}$

m = ρV

$m = \dfrac{4.5\times \rho}{\rho - \rho_0}$

$m = \dfrac{4.5\times 2700}{2700 - 1.29}$

m = 4.5021 kg

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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm

stepan [7]

The object rises to a height of 20.4 m. So option C is correct.

Explanation:

initial velocity= Vi=20 m/s

final velocity at the top= Vf=0

acceleration= g=-9.8 m/s²

Vf²=Vi²+2gh

0= (20)²+2 (-9.8)h

-200=-9.8h

h=200/9.8

h=20.4 m

Thus the object rises to a height of 20.4 m

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4 years ago

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weqwewe [10]

Explanation:

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