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JulijaS [17]
3 years ago
11

Two objects are connected by a string that passes over a frictionless pulley as in the figure below, where m1 < m2 and a1 and

a2 are the respective magnitudes of the accelerations. Which mathematical statement is true concerning the magnitude of the acceleration a2 of mass m2?
1. a2 = g
2. a2 < g
3. a2 > g
4. a2 > a1
5. a2 < a1
Physics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:2

Explanation:

Given

m_2>m_1

and a_1 and a_2 are the acceleration of 1 and 2

Suppose  T is the Tension

then for block 2

m_2g-T=m_2a

m_2(g-a)=T---1

For block 1

T-m_1g=m_1a

T=m_1(g+a)----2

equate 1 and 2

m_2(g-a)=m_1(g+a)

a=\frac{m_2-m_1}{m_1+m_2}

where a=a_1=a_2

thus we can see that a is less than g

therefore a_2 < g

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Most grandfather clocks have pendulums with adjustable lengths. One such clock gains 10 min per day when the length of its pendu
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The length to which the pendulum will be adjusted to keep perfect time is 29.59 inches. See the explanation below.

<h3>What is the justification for the above answer?</h3>

T1 = 2πR√(L1/GM)

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T2 = 2πR√(L1/GM)

T1/T2 = √(L1/L2).

If the pendulum has an efficient period, that means it executes with perfect frequency.

Thus,

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= 1440/x

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If the other Pendulum is slower by 10 minutes, that means

T1 = 1450/x

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(1450/x)/(1440/x) = √(L1/L2).

⇒ 1450/1440 = √(L1/L2).

Thus,

(1450/1440)² = 30/L

L = 30/(1450/1440)²

L = 30/(1.00694444444)²

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Hence, the pendulum will need to be adjusted by 29.59 inches to ensure that the clock keeps perfect time.

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brainly.com/question/16617199

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<u> </u>

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