An ice cube causes hot coffee to become cool because the amount of coldness contrasts the hot coffee to make it a little cooler
Answer:
A. 1.64 J
Explanation:
First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

where
n is the number of moles
m = 1.4 mg = 0.0014 g is the mass of mercury
Mm = 200.6 g/mol is the molar mass of mercury
Substituting, we find

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

where
n is the number of moles
is the Avogadro number
Substituting,
atoms
The energy emitted by each atom (the energy of one photon) is

where
h is the Planck constant
c is the speed of light
is the wavelength
Substituting,

And so, the total energy emitted by the sample is

Try this option, the answers are marked with colour.
Answer:
25
Explanation:
Given:
1 can of concentrate requires 3 cans of water
Now,
Total ounces in 200 6-ounce cans = 1200 ounces
also,
for 1 can of concentrate requires 3 cans of water
thus,
for 12 ounces can water can required = 3 × 12 ounces = 36 ounces of cans
Thus,
total ounce of juice per can = 12 + 36 = 48 ounces per can
therefore,
the number of 12-ounce cans required are = 
or
= 
or
the number of 12-ounce cans required are = 25