To solve this problem we will apply the Heisenberg indeterminacy relationship principles. The principle establishes the impossibility of certain pairs of observable and complementary physical quantities being known with arbitrary precision. If several identical copies of a system are prepared in a given state, such as an atom, the measurements of position and amount of movement will vary according to a certain probability distribution characteristic of the quantum state of the system. The measurements of the observable object will suffer standard deviation Δx of the position and the moment Δp. They then verify the principle of indeterminacy that is expressed mathematically as:
Here
h = Planck's constant
We have then,
Replacing our values we have that
<em>Note that the value substituted is the direct division between the Planck constant and the constant </em><em />
Now the speed will be taken from the momentum expression that defines as
Remember that the momentum is the product between mass and velocity, replacing we will have
Balanced forces do not result in any change in motion. forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion.
If the disk is initially at rest, and it is applied a constant force tangential to the rim, we can apply the following expression (that resembles Newton's 2nd law, applying to rigid bodies instead of point masses) as follows:
Where τ is the external torque applied to the body, I is the rotational inertia of the body regarding the axis of rotation, and α is the angular acceleration as a consequence of the torque.
Since the force is applied tangentially to the rim of the disk, it's perpendicular to the radius, so the torque can be calculated simply as follows:
τ = F*r (2)
For a solid uniform disk, the rotational inertia regarding an axle passing through its center is just I = m*r²/2 (3).
Replacing (2) and (3) in (1), we can solve for α, as follows:
Since the angular acceleration is constant, we can use the following kinematic equation:
Prior to solve it, we need to convert the angle rotated from revs to radians, as follows:
Replacing (6) in (5), taking into account that ω₀ = 0 (due to the disk starts from rest), we can solve for ωf, as follows:
Now, we know that there exists a fixed relationship the tangential speed and the angular speed, as follows:
where r is the radius of the circular movement. If we want to know the tangential speed of a point located on the rim of the disk, r becomes the radius of the disk, 0.200 m.
Replacing this value and (7) in (8), we get:
b)
There exists a fixed relationship between the tangential and the angular acceleration in a circular movement, as follows:
where r is the radius of the circular movement. In this case the point is located on the rim of the disk, so r becomes the radius of the disk.
Replacing this value and (4), in (9), we get:
Now, the resultant acceleration of a point of the rim, in magnitude, is the vector sum of the tangential acceleration and the radial acceleration.
The radial acceleration is just the centripetal acceleration, that can be expressed as follows:
Since we are asked to get the acceleration after the disk has rotated 0.2 rev, and we have just got the value of the angular speed after rotating this same angle, we can replace (7) in (11).
Since the point is located on the rim of the disk, r becomes simply the radius of the disk,, 0.200 m.
Replacing this value and (7) in (11) we get:
The magnitude of the resultant acceleration will be simply the vector sum of the tangential and the radial acceleration.
Since both are perpendicular each other, we can find the resultant acceleration applying the Pythagorean Theorem to both perpendicular components, as follows:
Answer:As sunlight passes through the atmosphere, all UVC and most UVB is absorbed by ozone, water vapour, oxygen and carbon dioxide. UVA is not filtered as significantly by the atmosphere. Is there a connection between ozone depletion and UV radiation? Ozone is a particularly effective absorber of UV radiation.