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Leni [432]
3 years ago
6

Can someone help asap plz don’t understand how to do this

Physics
1 answer:
shtirl [24]3 years ago
3 0
Homie I don’t know either‍♀️Drop out of schl ig ;-;
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A wave pulse travels along a string at a speed of 230 cm/s . Note that parts a - d are independent and refer to changes made to
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a) The speed of the wave will increase by a factor \sqrt{2}.

b) The speed of the wave will halve

c) The speed of the wave will double

Explanation:

a)

The speed of a standing wave on a string is given by

v=\sqrt{\frac{T}{m/L}}

where

T is the tension in the string

m is the mass of the string

L is the length of the string

In this part of the problem, the tension in the string is doubled, so that the new tension is

T' = 2T

Substituting into the equation, we find the new speed of the wave in the string:

v'=\sqrt{\frac{T'}{m/L}}=\sqrt{\frac{2T}{m/L}}=\sqrt{2}\sqrt{\frac{T}{m/L}}=\sqrt{2}v

So, the speed will increase by a factor \sqrt{2}.

b)

We can solve also this part by referring to the formula

v=\sqrt{\frac{T}{m/L}}

where

T is the tension

m is the mass

L is the length

In this case, the string mass is quadrupled, so the new mass is:

m' = 4m

Substituting into the equation, we find what happens to the speed of the wave:

v'=\sqrt{\frac{T}{m'/L}}=\sqrt{\frac{T}{4m/L}}=\frac{1}{\sqrt{4}}\sqrt{\frac{T}{m/L}}=\frac{1}{2}v

So, the speed of the wave will halve.

c)

Again, we can solve this part by referring to the same equation

v=\sqrt{\frac{T}{m/L}}

where

T is the tension

m is the mass

L is the length

In this case, the length of the string is quadrupled, so the new length is:

L' = 4L

Substituting into the equation, we find that the new speed is:

v'=\sqrt{\frac{T}{m/L'}}=\sqrt{\frac{T}{m/(4L)}}=\sqrt{4}\sqrt{\frac{T}{m/L}}=2v

So, the speed of the wave will  double.

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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