Find a number that goes into both 64 and 40 the GCF of both is 8 so 8 goes on the outside of the new factor 8u-5 because if we distribute back we should arrive at the original equation
You need to solve 10^6 * 10^2 without using standard notation. As with variables, if you had x^6 * x^2 you would add the exponents. Replace x with 10. Your answer is 10^8. As a sidenote, only multiply exponents when raising a power to another power, e.g. (10^6)^2 = 10^12.