Question

A jar contains 38 marbles. It has 10 red, 22 black and 6 green marbles. Two marbles are drawn, the first is not returned before the second one is drawn. What is the probability that both marbles are black?
P(Both Black) = 11 / 19

P(Both Black) = 231 / 703

P(Both Black) = 231 / 722

P(Both Black) = 121 / 361

Answer 1

Answer:

The correct answer option is 231 / 703

Step-by-step explanation:

We are given that a jar has 38 marbles, out of which 10 are red, 22 are black and 6 are green. Two marbles are drawn and the first marble is not returned when the second one is drawn.

We are to find the probability that both marbles are black.

1st draw: P (black) = $\frac{22}{38} =\frac{11}{19}$

2nd draw: P (black) = $\frac{21}{37}$

P (Both Black) = $\frac{11}{19} \times \frac{21}{37}$ = 231 / 703