From the function given:
y=x^2-5
this can be written as:
y=x^2+0x-5
writing in vertex form we get:
y=(x-h)^2+k
where: (h,k) is the vertex
y=(x-0)^2-5
thus the vertex is at (0,-5)
the parent function is y=x^2, thus the graph of the parent function is First graph
Answer:
0
Step-by-step explanation:
A= (4-1)^3
simplify A to be 3^3
Which gives us 27
B=(2*3)^2-9
simplify B
first multiply the 2 numbers in paranthesis which gives us 6. raise it to the power of 2 which is 39 and then subtract 9. Gives us 27.
C=15^3*4-12
Simplify the exponent first. 3*4 gives us 12 and 12-12 equals 0. Anything raised to the power of 0=1
If A-B^C is the equation we can write 27-27 raised to the power of 1 which is 0
Answer:4=12
Step-by-step explanation:
Answer:
A.) 
Step-by-step explanation:
f(-2) means plug in -2 in for x for the equation f(x), therefore,
f(-2) = 
