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elena55 [62]
3 years ago
11

While on a camping trip, Calvin was monitoring the temperature. In the afternoon, the temperature was -4°C. As the evening progr

essed, the temperature dropped 7°C. By mid-morning the next day, the temperature had risen 3°C. What was the temperature, in degrees Celsius, after these changes?
Mathematics
2 answers:
qaws [65]3 years ago
8 0

Answer:

over c

Step-by-step explanation:

saul85 [17]3 years ago
7 0

Answer:

8 degrees Celsius

-4 -7 = -11

-11+3 = 8

Step-by-step explanation:

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Given Ohm's Law, V=IR<br> which of the following operations will solve for I<br> I?
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5 0
3 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
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