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EastWind [94]
3 years ago
15

2 1⁄4 × 1 1⁄2 × 5⁄3 =

Mathematics
1 answer:
omeli [17]3 years ago
8 0

Answer:

45/8 = 5,625

Step-by-step explanation:

2\frac{1}{4} × 1\frac{1}{2} × \frac{5}{3} = 9/4 × 3/2 × 5/3 = 9/4 × 1/2 × 5 = 45/8 = 5,625

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I need the help ASAP, please and thank you :)
SVEN [57.7K]

Answer: Im struggling to understand this one and im in highschool my brain is melting.

Step-by-step explanation:

3 0
2 years ago
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A pair of jeans originally cost $80, but is on sale for 30% off. there is a coupon available for an additional 10% off of the sa
Lady_Fox [76]
30% = 0.3. 

0.3*80 = 24, so we know that 30% of 80 is 24. 

80 - 24 = 56, so after the sale, the price for a pair of jeans is $56.

10% = 0.1

0.1*56 = 5.6, so with the coupon, we get $5.60 off. 

56 - 5.60 = 50.40

The jeans cost $50.40 after the sale and the coupon. 
5 0
3 years ago
Can you please help with both? :)​
QveST [7]

Answer: 1. 12 2. 120

Step-by-step explanation:

1. so basically 9/6=18/x

since they are similir the'd have the same ratio

sooo you just solve for x (multiply 6 by 18, and then divide by 9) and you get 12

2. same thing except you put 6/10=12/x, and solve it (multiply 10 by 12 and divide by 6) and u get 20

dats how i would do it but there are other ways too im sure :)

hope this helps

8 0
3 years ago
Help please The question is in the photo
Sergio039 [100]
I believe the answer to your question is 23
5 0
3 years ago
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A commuter must pass through 5 traffic lights on her way to work and will have to stop at each one that is red. She estimates th
sergij07 [2.7K]

Answer:

(a) The mean or expected value of <em>X </em>is 2.2.

(b) The standard deviation of <em>X</em> is 1.3.

Step-by-step explanation:

Let <em>X</em> = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of <em>X</em> id provided.

The formula to compute the mean or expected value of <em>X </em>is:

\mu=E(X)=\sum x.P(X=x)

The formula to compute the standard deviation of <em>X </em>is:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}

The formula of E (X²) is:

E(X^{2})=\sum x^{2}.P(X=x)

(a)

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2

Thus, the mean or expected value of <em>X </em>is 2.2.

(b)

Compute the value of E (X²) as follows:

E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58

Compute the standard deviation of <em>X</em> as follows:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3

Thus, the standard deviation of <em>X</em> is 1.3.

4 0
3 years ago
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