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3 years ago

Plz solve this question..Its urgent..

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

Step-by-step explanation:

In circle with centre O, TN is tangent at E.

$\therefore OE \perp TN\\\\\therefore m\angle OET = m\angle OEN= 90\degree \\\\In\: \triangle OET\\\\\angle OET + \angle OTE +\angle TOE = 180°\\\\\therefore 90\degree + 35\degree+\angle TOE = 180°\\\\\therefore 125\degree+\angle TOE = 180\degree\\\\\therefore \angle TOE = 180\degree-125\degree\\\\\huge \red {\boxed{\therefore \angle TOE = 55\degree}} \\\\In\: \triangle OPE\\\\OP = OE... (radii\: of \:same \: circle) \\\\\therefore \angle OPE = \angle OEP..(1)\\ (\angle s \: opposite \: to \:equal\:sides) \\\\\angle TOE =\angle OPE +\angle OEP.. (2)\\(by\:exterior \:\angle\:theorem) \\\\\therefore 55\degree= \angle OPE +\angle OPE\\\{From\: equations\:(1) \&\:(2)\} \\\\\therefore 55\degree= 2\angle OPE \\\\\therefore \angle OPE = \frac{55\degree}{2}\\\\\huge \orange{\boxed{\therefore \angle OPE =27.5\degree}}$

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Will give BRAINLEST :)

DiKsa [7]

Answer:

Step-by-step explanation:

This explanation mostly depends on what you're learning right now. The first way would be to convert this matrix to a system of equations like this.

g + t + k = 90

g + 2t - k = 55

-g - t + 3k = 30

Then you solve using normal methods of substitution or elimination. It seems to me that elimination is the quickest method.

g + t + k = 90

-g - t + 3k = 30

____________

0 + 0 + 4k = 120

4k = 120

k = 30

No you can plug this into the first two equations

g + t + (30) = 90

g + t = 60

and

g + 2t - (30) = 55

g + 2t = 85

now use elimination again by multiplying the first equation by -1

g + 2t = 85

-g - t = -60

_________

0 + t = 25

t = 25

Now plug those both back into one of the equations. I'll just do the first one.

g + (25) + (30) = 90

g = 35

Therefore, we know that Ted spent the least amount of time on the computer.

The second method is using matrix reduction and getting the matrix in the row echelon form, therefore solving using the gauss jordan method. If you would like me to go through this instead, please leave a comment.

3 0

2 years ago

a cartographer used a scale of 1 inch :300 meters for the heights of different mountains if the actual height of one of those mo

zaharov [31]

Answer:

$12\frac{1}{3}$ inches

Step-by-step explanation:

So to go from 300 to 3700 you have to multiply by $12\frac{1}{3}$

7 0

3 years ago

By what percent change if the numerator is decreased by 10% and the denominator is decreased by 70%

hjlf

Answer:

It increases x3.

Step-by-step explanation:

Let's say the fraction to begin with was 100/100. Ignore the fact that it isn't fully reduced and it is an improper fraction.

10% of 100 is 10, so the numerator is now 90 (decrease=get smaller; 100-10=90).

70% of 100 is 70, so the denominator is now 30 (decrease=get smaller; 100-70=30).

Our fraction is now 90/30 which, when fully reduced, equals 3.00. Since 100/100 equals 1.00, it has increased by 2.00 (3x bigger).

6 0

2 years ago

Can someone help me with this? thank you!

Vedmedyk [2.9K]

Answer:

V = 240 $cm^{3}$

Step-by-step explanation:

To find the volume of a rectangular prism use this equation:

V = l*w*h

l = length (20 cm)

w = width (4 cm)

h = height (3 cm)

Plug all these values into the equation and solve:

V = (20 cm)(4 cm)(3 cm)

V = (80 $cm^{2}$ )(3 cm)

V = 240 $cm^{3}$

Therefore, the volume of the rectangular prism is 240 $cm^{3}$ .

I hope this helps! Good luck!

8 0

2 years ago

Enter the number of complex zeros for the polynomial function in the box.

Finger [1]

Given polynomial function:

$f(x)=x^3-96x^2+400$ .

We need to apply Descartes' rule of sign to identify the number of complex roots.

The given polynomial is f(x)=x^3-96x^2+400

Let us see the number of sign changes in f(x)

There are 2 sign changes in f(x). One from plus to minus and second from plus to minus. Hence, there 2 or 0 positive roots.

Now, let us see the number of sign changes in f(-x)

f(-x)=-x^3-96x^2+400

There are only one sign change. Hence, there will be 1 negative roots.

The degree of the polynomial is 3.

Hence, there will be exactly 3 zeros.

<em>Therefore, the possible numbers of zeros are:</em>

<em>2 positive, 1 negative and 0 complex</em>

<em>0 positive, 1 negative and 2 complex.</em>

Let us see the graph:

In the graph, we can see that the graph cuts the x axis at three points (2 positive, 1 negative points).

<h3>Hence, the number of complex zeros for the given polynomial is zero.</h3>

3 0

2 years ago

Plz solve this question..Its urgent..​

Plz solve this question..Its urgent..