Answer:
2. Co(NO3)2 + H2
Explanation:
Hello,
In this case, we are evidencing a simple displacement reaction wherein the cobalt is able displace the hydrogen to produce cobalt (II) nitrate and gaseous hydrogen as a result of cobalt's higher activity:
Therefore, answer is 2. Co(NO3)2 + H2.
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Answer:
concentration of = 0.0124 = 12.4 ×10⁻³ M
concentration of = 0.0248 = 2.48 ×10⁻² M
concentration of = 0.4442 M
Explanation:
Equation for the reaction:
⇄
+
Concentration of =
= 0.469
For our ICE Table; we have:
⇄
+
Initial 0.469 0 0
Change - 2x +2x +x
Equilibrium (0.469-2x) 2x x
K =
K =
Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²
x = 0.0124
∴ at equilibrium; concentration of = 0.0124 = 12.4 ×10⁻³ M
concentration of = 2x = 2 ( 0.0124)
= 0.0248
= 2.48 ×10⁻² M
concentration of = 0.469-2x
= 0.469-2(0.0124)
= 0.469 - 0.0248
= 0.4442 M