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Anika [276]
3 years ago
11

If you have exactly 2.00 moles each, of two different substances, then which of the following must be true about the two samples

?
Chemistry
1 answer:
Gwar [14]3 years ago
4 0
The true is that both substances will have 2 * 6.02* 10^23 = 12.04 * 10^23 particles (may be molucules or atoms(.

Also, the two moles of each substance will have different masses, because you have to multiply the number of moles of each substance by the respective molar mass (or atomic mass).


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A substance has a high melting point and conducts electricity in the liquid phase The is substance is
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oxygen

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Barium carbonate  barium oxide and carbon dioxide balanced formula HELP ME PLEASE
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Answer:

4Ba(CO3) -> 4BaO2 + 2CO2

Explanation:

I looked at the oxygens to balance this. Ba(CO3) normally has 3 oxygens. BaO2 and CO2 have 4 oxygens total. The common multiple of 3 & 4 is 12. So there should be 12 oxygens on both sides. Then I just found the coefficients that would give 12 oxygens on both sides and can balance the rest of the atoms.

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Which of the following shows a coefficient?
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6 0
3 years ago
Enthalpy of combustion of ethyl alcohol, C2 H5 OH, is – 950 kJ mol–1. How much heat is evolved when one gram of ethyl alcohol bu
melomori [17]
<h3>Answer:</h3>

20.62 Kilo-joules

<h3>Explanation:</h3>
  • The Enthalpy of combustion of ethyl alcohol is -950 kJ/mol.
  • This means that 1 mole of ethyl alcohol evolves a quantity of heat of 950 Joules when burned.

Molar mass of ethyl ethanol = 46.08 g/mol

Therefore;

46.08 g of  C₂H₅OH evolves heat equivalent to 950 kilojoules

We can calculate the amount of heat evolved by 1 g of C₂H₅OH

Heat evolved by 1 g of C₂H₅OH  = Molar enthalpy of combustion ÷ Molar mass

                                      = 950 kJ/mol ÷ 46.08 g/mol

                                      = 20.62 Kj/g

Therefore, a gram of C₂H₅OH  will evolve 20.62 kilo-joules of heat

7 0
3 years ago
PLEASE HELP!! 40 POINTS
PSYCHO15rus [73]

Answer:

1) 6.524779402×10^(-17)  

2)521.1g

3)113

Explanation:

5 0
3 years ago
Read 2 more answers
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