Answer:

Explanation:
As we know that the ball swings out to maximum angle of 50 degree
so we will have use energy conservation to find the initial speed of the ball


so we have


now we can use momentum conservation for this collision



also we know that it is elastic collision
so we will have

now from above two equations we have

2.78 X 10^5 is the best answer to be responded to
Answer:
The phases are the first and third quarters.
Explanation:
During the first quarter of the moon phases, the line between Earth and the Sun is at a right angle to the line between Earth and the moon. At this time the moon has completed the first quarter of its orbit around the earth. At this point, half of the moon is fully reflecting light from the sun.
Also during the third quarter which is the last quarter, the line between the earth and the sun is at a right angle to the line between the earth and the moon. This is the time when the second half of the moon which was not illuminated during the first quarter becomes completely illuminated.
Answer:
The speed of car leaves Vernonville = 45 miles per hour
The speed of car leaves Salem = 55 miles per hour
Explanation:
Given that distance between Salem and Vernonville = 160 miles
Lest take speed of car which leaves from Vernonville = V miles per hour
So the speed of car which leaves from Salem = V +10 miles per hour
These two car meet at time = 1 hr 36 min = 1.6 hr
Distance travel by car leaves from Salem = x
x= (V+10) x 1.6 --------1
Distance travel by car leaves from Vernonville = 160 - x
160 - x= V x 1.6 ----------2
From equation 1 and 2
160 - (V+10) x 1.6 = V x 1.6
V= 45 miles per hour
So
The speed of car leaves Vernonville = 45 miles per hour
The speed of car leaves Salem = 55 miles per hour
We use the Planck’s formula:
E = hv
where,
E = energy, h = planck’s constant = 6.6x10^-34 J s, v =
frequency in Hz (Hz = 1 / s)
Subsituting the values to find for E:
E = (6.6×10^-34 J s) * 9.85×10^14 / s
E = 6.5x10^-19 J