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3 years ago

Which would be most reliable source for information about the toxity of an industrial chemical

2 answers:

6 0

For example, a trade secret may be a confidential device, pattern, information, or chemical make-up.Chemical industry trade secrets are generally formulas, process data, or a "specific chemical identity." The latter is the type of trade secret information referred to in the Hazard Communication Standard. The term includes

inn [45]3 years ago

3 0

A scientific journal that was peer reviewed :)

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Which of the following units would be used for measuring volume?

zalisa [80]

i am right their with you i do believe it is A or D but i am more certain of D

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3 years ago

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed?(a) 16(b

maw [93]

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

<h3>What is kinetic energy?</h3>

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

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1 year ago

Rank the deformations of the following rods in terms of the magnitude of the average normal strain: (a) The length of a 1-m-long

kipiarov [429]

To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

$\epsilon = \frac{\delta}{l} = \frac{l_0-l}{l}$

Here,

$\delta$ = Change in final length $(l_0)$ and the initial length $l$

PART A)

$\epsilon = \frac{\delta_1}{l}$

$\epsilon = \frac{l_0-l}{l_0}$

$\epsilon = \frac{1.02-1}{1}$

$\epsilon = 0.01961$

PART B)

$\epsilon = \frac{\delta_1}{l}$

$\epsilon = \frac{l_0-l}{l_0}$

$\epsilon = \frac{2-1.05}{2}$

$\epsilon = 0.475$

PART C)

$\epsilon = \frac{\delta_1}{l}$

$\epsilon = \frac{l_0-l}{l_0}$

$\epsilon = \frac{3.07-3}{3}$

$\epsilon = 0.0233$

Therefore the rank of this deformation would be B>C>A

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3 years ago

PLEASE HLEP IM BEING TIMED, I WILL GIVE BRANLIEST IF U R RITEEEEEEEEEEEEEEE

netineya [11]

D) igneous
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4 years ago

Please help me on this position-time graph assignment!!!

saw5 [17]

$\text{Hello there! :)}$

$\text{The velocity is essentially the slope of the graph in a position vs. time graph, so:}$

$\text{Given: From 0 - 8 sec, velocity of 10 m/s.}\\\\\text{From 8 - 18 sec, velocity of -5 m/s. (In opposite direction because of the negative sign)}\\\\\\\text{From 18 - 22 sec, velocity of 0 m/s. (Object at rest)}\\\\\text{From 22 - 24 sec, velocity of 5 m/s.}\\\\\text{Graph the position vs. time graph using the velocities as the slope of the line }$

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4 years ago