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PSYCHO15rus [73]
3 years ago
13

Which would be most reliable source for information about the toxity of an industrial chemical

Physics
2 answers:
amid [387]3 years ago
6 0
For example, a trade secret may<span> be a confidential device, pattern, </span>information<span>, or </span>chemical<span> make-up.</span>Chemical industry<span> trade secrets are generally formulas, process data, or a "specific </span>chemical<span> identity." The latter is the type of trade secret </span>information<span> referred to in the Hazard Communication Standard. The term includes</span>
inn [45]3 years ago
3 0

A scientific journal that was peer reviewed :)

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Calculate the index of refraction for a medium in which the speed of light is 1.239 ✕ 108 m/s. (The speed of light in vacuum is
True [87]

Answer:

Refractive index, n = 2.419

Explanation:

It is given that,

Speed of light in the medium, v=1.239\times 10^8\ m/s

Speed of light in the vacuum, c=2.998\times 10^8\ m/s

Let n is the index of refraction for a medium. We know that the refractive index for any medium is equal to the ratio of speed of light in vacuum to the speed of light in medium. It can be written as :

n=\dfrac{c}{v}

n=\dfrac{2.998\times 10^8\ m/s}{1.239\times 10^8\ m/s}

n = 2.419

So, the index of refraction for a medium is 2.419. Hence, this is the required solution.

3 0
3 years ago
A golfer hits a golf ball at an angle of 30 degrees from the ground, with an initial velocity of 120 ft/sec. It lands on the gro
Gelneren [198K]
Data:

Vo = 120 ft / s

α = 30°

t = 5 s

x = ?

Formulas:

cos(α) = Vo,x / Vo => Vo,x = Vo * cos(α)

x = Vo,x * t

Calculations:

Vo,x = 120 ft / s * cos(30) = 103.92 ft /s

x = 103.92 ft/s * 5 s = 519.6 ft

Answer: 519.6 ft
8 0
3 years ago
A swimming pool measures 5.0 m long x 4.0 m wide x 3.0 mdeep.
QveST [7]

Answer:

a) 588,000 N

b) 294000 N

Explanation:

Given that

Density of water = 1000kg/m3

(g) = 9.8m/s2

volume is given as (V)= 5m*4m*3m

a) force will be equal to weight of water

W = mg  = \rho g V = 1000\times 9.8 \times (5*4*3) = 588,000 kg m/s^2

b) at either end

P = \frac{F}{A} = P_o + \rho gh

dF = PdA

dF = \rho g w \int h dh

F = \rho g w \frac{h^2}{2}

F = \rho g A \frac{h}{2}           [A = wh]

F = 1000\times 9.8 \times 5\times 4 \times\frac{3}{2}

F = 294000 N

3 0
3 years ago
Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, wh
mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

Given

Both cars mass is m

and solving problem in Vertical and horizontal direction

considering + y and +x to be positive and u be the final velocity of system

Conserving Momentum in Vertical direction

m(2v)+m(-vsin\phi )=2m(ucos\theta )

2ucos\theta =v(2-sin\theta )------1

Conserving momentum in x direction

mvcos\phi =2musin\theta-----2

squaring and adding 1 &2

(2u)^2=(2v-vsin\phi )^2+(vcos\phi )^2

4u^2=4v^2+v^2-4v^2sin\phi

4u^2=5v^2-4v^2sin\phi

u=\frac{v}{2}\sqrt{5-4sin\phi }

7 0
3 years ago
Not sure if it went through last time. Please help asap!
Olin [163]
The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
0.42 \times 14.8 = 6.22
The answer is 6.22 N because newtons are the unit used to measure force.
8 0
3 years ago
Read 2 more answers
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