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galben [10]
2 years ago
7

What is a formula unit​

Physics
1 answer:
Nana76 [90]2 years ago
3 0

A formula unit is the empirical formula for an ionic compound. It is the lowest possible ratio of the cations and anions of a given ionic compound.

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engineers are using computer models to study train collisions design safer train cars. They start by modeling an elastic collisi
Archy [21]

Answer:

The final velocity of the second car is 57 m/s south.

Explanation:

This is an elastic collision between two train cars. In this case, the total kinetic energy between the two bodies will remain the same.

The formula to apply is :

m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f

where ;

m_1=mass of object 1\\v_1i=initial  velocity object1\\m_2=mass of object2\\v_2i=initial velocity object 2\\v_1f=final velocity object 1\\v_2f=final velocity object 2

Given in the question that;

m_1=14650kg\\v_1i=18m/s\\m_2=3825kg\\v_2i=11m/s\\v_1f=6m/s\\v_2f=?

Apply the formula as;

m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f

{14650*18}+{3825*11} = {14650 *6} + {3825 * v₂f}

263700+42075=87900 + 3825v₂f

305775 =87900 + 3825v₂f

305775-87900 = 3825v₂f

217875=3825v₂f

217875/3825 =v₂f

56.96 = v₂f

<u>57 m/s = v₂f { nearest whole number}</u>

4 0
2 years ago
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Visible light energy.
Ipatiy [6.2K]
What about it??

Please explain and I will help.

I don’t know what you’re asking.
6 0
3 years ago
Read 2 more answers
When water diffuses across a semi permeable membrane the process is called __________.
expeople1 [14]
Osmosis !!!!!!!!!!!!!!!!!!
6 0
2 years ago
How much work is required to turn an electric dipole 180° in a uniform electric field of magnitude E = 46.0 N/C if the dipole mo
chubhunter [2.5K]

Answer:

W=1.22*10^{-23}J

Explanation:

Torque and energy of an electric dipole in an electric field we find:

W=U(\alpha_{o}+\pi  )-U(\alpha_{o} )=-pE(cos(\alpha_{o}+\pi )-cos(\alpha_{o} ))\\W=2pECos\alpha_{o}\\ W=2(3.02*10^{-25}C.m )(46.oN/C)Cos64\\W=1.22*10^{-23}J

3 0
3 years ago
A spring with a force constant of 5.2 N/m has a relaxed length of 2.45 m. When a mass is attached to the end of the spring and a
Elodia [21]

Answer:

Elastic potential energy, E = 3.26 J

Explanation:

It is given that,

Force constant of the spring, k = 5.2 N/m

Relaxed length of the spring, X = 2.45 m

When the mass is attached to the end of the spring, the vertical length of the spring is, x' = 3.57 m

To find,

The elastic potential energy stored in the spring.

Solution,

The extension in the length of the spring is given by :

x=x'-X

x=3.57\ m-2.45\ m

x = 1.12 m

The elastic potential energy of the spring is given by :

E=\dfrac{1}{2}kx^2

E=\dfrac{1}{2}\times 5.2\times (1.12)^2

E = 3.26 J

So, the elastic potential energy stored in the spring is 3.26 joules.

6 0
3 years ago
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