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blagie [28]
3 years ago
5

A group of 15 friends travel to Washington DC. 2/5 go by bus, 1/3 by metro, and the rest by car. What fraction went by car? How

many people went by bus? Metro? Car?
Mathematics
1 answer:
tester [92]3 years ago
7 0

Answer:

14 4/5 went by car.

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Vlad [161]
The distance of BF is 7.07
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Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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Distribute. -3(-2x - 1)
ANTONII [103]

I believe the answer should be 6x+3

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A walkway goes through the middle of a square playground from one corner to the opposite corner. If the walkway is 20 meters lon
Dahasolnce [82]
I think you would use the Pythagorean Theorem to solve this, as a square cut across diagonally creates two isocele triangles. Since the longest side is 20 m, this value would be imputed into c^2.

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Thus, each sides of the playground are 14.14 meters long.

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Suppose that 15% of the general population has a disease and the test for the disease is accurate 80% of the time. What is the p
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<span>C. 23% this is yur answer hope i helped</span>
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