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emmasim [6.3K]
3 years ago
15

If 5 times a number is subtracted from 3 times itssquare, the result is 2. Find the number.​

Mathematics
1 answer:
grandymaker [24]3 years ago
5 0

Answer:

x = 2 or x = - 1/3

Step-by-step explanation:

3x² - 5x = 2

3x² - 5x - 2 = 0

(x - 2) (3x + 1) = 0

x = 2 or x = - 1/3

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6 0
3 years ago
Read 2 more answers
I need some help on this math problem, thanks so much
bekas [8.4K]

Answer:

The answer is C.

Step-by-step explanation:

Hit 'em with the Law of Sines.

sin(A)/a = sin(B)/b.

Let's say x is equal to "A", thus 5 is "a".

sin(x)/5 = sin(B)/b.

We could go for the obvious choice for "B", which would be the 90 degrees shown. To solve for the hypotenuse which will be "b", let's use the Pythagorean Theorem:

a^2 + b^2 = c^2

5^2 + 20^2 = c^2

25 + 400 = 425

sqrt(425) = about 20.6, which we can now substitute "b" with.

sin(x)/5 = sin(90)/20.6

sin(x)/5 = 1/20.6

sin(x)/5 = 0.04854...

sin(x) = 0.2427...

You can plug in sin^-1(0.2427) into your calculator, and you should end up with something like 14.047... which equates to answer choice C.

6 0
3 years ago
Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.
Olenka [21]

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}

step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}

\frac{(x-3)(9-x)}{3x(x-3)}

step 3

simplify

\frac{(9-x)}{3x}

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%2B%7Cx%2B1%7C%5C%20%5Ctextgreater%20%5C%200" id="TexFormula1" title="5x^{2}+|x+1|
Pavel [41]
5x² + |x+1| > 0
5x² + x + 1 > 0
x+1 > 0 because it came from absolute
5x² > 0 because it’s squared

When you try a number you should put it in the original equality
5x² + |x+1|
7 0
2 years ago
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